Given :
Miki has 104 nickels and 88 dimes.
She wants to divide her coins into groups where each group has the same number of nickels and the same number of dimes.
To Find :
Largest number of groups she can have .
Solution :
In the given question we need to find the largest number of groups she can have i.e we have to find the LCM of 104 and 88 .
Now , factorizing both of them , we get :
Form above , we can say that common factors are :
Therefore , the largest number of groups she can have is 8 .
Hence , this is the required solution .
Answer:
the answer is x4sqaured=2
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Step-by-step explanation:
I believe the answer is 5 mph east
Okay, so this is actually relatively simple:
Go up 44 units on the y-axis, where x=0, and put a point. Now, since the slope is 3x, you move 3 units up, and 1 unit right, and place a point. Do this about 3 times, continuing to make points up 3, over 1. You can also move 3 units down and 1 unit left from the point at (0,44) because by moving down, you move -3 units, and by moving left, you move -1 units. This causes the negatives to cancel out, and you keep the slope of 3.
I hope this explanation makes sense; good luck!
To solve algebraically:
Plug in any number for x, besides 0 because the y-intercept is (0,44). We will use 1 for our x.
y=44+3x
y=44+3(1)
y=44+3
y=47
And so, (1, 47) would be our point
You can use -1, as well.
y=44+3(-1)
y=44-3
y=41
(-1, 44) would be our point
