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4 years ago

5 min 0 sec minus 35 sec

Mathematics

1 answer:

nata0808 [166]4 years ago

5 0

4 minutes and 25 seconds

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Which quadratic regression equation best fits the data set?

nata0808 [166]

Answer: $y = 1.87x^2 -5.16 x + 10.54$

Step-by-step explanation:

Since the general quadratic equation is,

$y = ax^2 + bx+c$

Here the given table is,

x 1 2 3 4 5 6 7

y 5.9 8.9 13.4 20.1 30.1 45.1 67.7

By the graphing calculator,

a = 1.87024 ≈ 1.87

b= -5.15833 ≈ -5.15

c = 10.5429 ≈ 10.54

By putting the values of a, b and c,

The required quadratic equation is,

$1.87 x^2 -5.15x + 10.54$

⇒ First Option is correct.

6 0

4 years ago

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Solve.<br> 7 pounds x 16 ounces =<br> pounds plz hero

Rama09 [41]

The answer is 7 pounds because 16 ounces is equal to 1 pound so 7 pounds times 1 pound would equal 7 pounds.

4 0

3 years ago

Quanto é 40 de 45% preciso urgente

saw5 [17]

My Spanish isn't that great but I think you're looking for 18

5 0

4 years ago

NO LINKS!!! Find the arc measure and arc length of AB. Then find the area of the sector ABQ.

Norma-Jean [14]

Answer:

<u>Arc Measure</u>: equal to the measure of its corresponding central angle.

<u>Formulas</u>

$\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right)$

$\textsf{Area of a sector of a circle}=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2$

$\textsf{(where r is the radius and the angle }\theta \textsf{ is measured in degrees)}$

<h3><u>Question 39</u></h3>

Given:

r = 7 in
$\theta$ = 90°

Substitute the given values into the formulas:

Arc AB = 90°

$\textsf{Arc length of AB}=2 \pi (7) \left(\dfrac{90^{\circ}}{360^{\circ}}\right)=3.5 \pi=11.00\:\sf in\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{90^{\circ}}{360^{\circ}}\right) \pi (7)^2=\dfrac{49}{4} \pi=38.48\:\sf in^2\:(2\:d.p.)$

<h3><u>Question 40</u></h3>

Given:

r = 6 ft
$\theta$ = 120°

Substitute the given values into the formulas:

Arc AB = 120°

$\textsf{Arc length of AB}=2 \pi (6) \left(\dfrac{120^{\circ}}{360^{\circ}}\right)=4\pi=12.57\:\sf ft\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{120^{\circ}}{360^{\circ}}\right) \pi (6)^2=12 \pi=37.70\:\sf ft^2\:(2\:d.p.)$

<h3><u>Question 41</u></h3>

Given:

r = 12 cm
$\theta$ = 45°

Substitute the given values into the formulas:

Arc AB = 45°

$\textsf{Arc length of AB}=2 \pi (12) \left(\dfrac{45^{\circ}}{360^{\circ}}\right)=3 \pi=9.42\:\sf cm\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{45^{\circ}}{360^{\circ}}\right) \pi (12)^2=18 \pi=56.55\:\sf cm^2\:(2\:d.p.)$

8 0

2 years ago

What is 2 + 2 - 1 = ????

Snowcat [4.5K]

2 + 2 - 1 is 3. lol.

6 0

4 years ago

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