The value of x in the equation is 26. 087
<h3>What are algebraic expressions?</h3>
Algebraic expressions are defined as expressions made up of terms, constants, coefficients, factors and variables.
They may also include certain mathematical or arithmetic operations which includes;
- Bracket
- Division
- Addition
- Subtraction
- Parentheses
- Multiplication and so on
Given the equation;
(0.020) (0.030) / (0.10)x = 2.3 × 10-4
We can simply the equation following the steps;
expand the brackets, we have;
6× 10^-4/ 0.10x = 2.3 × 10^-4
Now, cross multiply
0.10x × 2.3 × 10^-4 = 6× 10^-4
Divide both sides by 2.3 × 10^-4
0. 10x = 6× 10^-4/2.3 × 10^-4
Find the quotient
0. 10x = 2. 608
Let's make the variable 'x' by dividing both sides by it's coefficient
0. 10x/0.10 = 2. 608/0. 10
x = 26. 087
Hence, the value is 26. 087
Learn more about algebraic expressions here:
brainly.com/question/4344214
#SPJ1
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
the equation is made and the included values are indicated.
The correct answer is 17 what i did was plug in 17 where ever you see x so x2 would be 17x2 an then plus the 5 gives u 39 3x 17x3=51 51+10=61 now add the totals 61 plus 39 gives u 100
Answer:
For edginuity the answer is the last one.
Step-by-step explanation :
You multiply 3 x 3 and it’s 9. Have a great day and stay positive during this pandemic!!