How much larger is the sum of 3x²-2x-8 and 4x²+2x-1 than the sum of 5x²-4x and 2x²-13x+4

1 answer:

8 0

That's

$\left( (3x^2-2x-8)+(4x^2+2x-1) \right) - \left( (5x^2-4x)+(2x^2-13x+4) \right)$

$= \left( 7x^2-9\right)-\left( 7x^2-17x+4 \right)$

$=17x-13$
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That much larger.

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