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4 years ago

For the equation y = 2x^2 − 5x + 18, choose the correct application of the quadratic formula.

Mathematics

1 answer:

andreev551 [17]4 years ago

7 0

Answer:

yes the answer is A .Step-by-step explanation: because 2x^2 is your a term and -5x is your b term and 18 is your c term and the quadratic formula is -b plus or minus the square root of b squared subtract 4ac all over 2a

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What is the answer is this problem?

USPshnik [31]

Answer:

First One = 0.000045 Second One = 0.024

Step-by-step explanation:

When 10 has a negative power, move the decimal to the right the number of times the power is. For example, 10^-5 is moved 5 places to the LEFT, so it is 0.000045.

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3 years ago

Joel has 59 songs on his MP3 player he equally divides them 7 groups how many songs will be in each group

Xelga [282]

Joel has 59 songs on his MP3 player he equally divides them 7 groups how many songs will be in each group

Total number of songs = 59

We need to divide them into 7 groups

so we divide 59 by 7

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4 years ago

What integer is equal to 9 3/2

Ad libitum [116K]

The correct answer is: 27 . 9^(3/2) = (√9)³ = 3³ = 3 * 3 * 3 = 27 .

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3 years ago

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Please help i have been struggling with this

Readme [11.4K]

Answer:

When put into a decimal, the answer is 0.09 recurring.

Step-by-step explanation:

Divide the numerator by the denominator to convert a fraction to a decimal. The entire number stays to the left of the decimal when there is a mixed number.

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2 years ago

Determine for which values of m the function variant Φ(x) = x^m is a solution to the given equation. a. 3x^2 (d^2y/dx^2) + 11x(d

miv72 [106K]

Answer:

a) m = -9 or m = 1

b) m = 1 + √6 or m = 1 -√6

Step-by-step explanation:

for

Φ(x) = x^m

then

dΦ/dx (x) = m*x^(m-1)

d²Φ/dx² (x) = m*(m-1)*x^(m-2)

then

for a

3x^2 (d^2y/dx^2) + 11x(dy/dx) - 3y = 0

3x^2*m*(m-1)*x^(m-2) + 11*x* m*x^(m-1) - 3*x^m = 0

3*m*(m-1)*x^m + 11*m*x^m- 3*x^m = 0

dividing by x^m

3*m*(m-1) + 11*m - 3 =0

3*m² + 8 m - 3 =0

m= [-8 ± √(64 + 4*3*3)]/2 = (-8±10)/2

m₁ = -9 , m₂= 1

then Φ(x) = x^m is a solution for the equation a , when m = -9 or m = 1

for b)

x^2 (d^2y/dx^2) - x(dy/dx) - 5y = 0

x^2*m*(m-1)*x^(m-2) - x* m*x^(m-1) - 5*x^m = 0

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dividing by x^m

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m² - 2 m - 5 =0

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7 0

3 years ago

Read 2 more answers