The amount of money that Phyllis invested at each given rate of 4 and 6 percent is = $394.57 and $591.86 respectively.
<h3>Calculation of the total capital invested</h3>
The time the investment lasted= 12 years.
Simple interest = 1579.05 - 800= $779.05
The principal capital= $800
Rate of the both capital invested;
= SI × 100/P ×T
= 779.05 × 100/800 × 12
= 77,905/9600
= 8.11%
To find the amount of money that Phyllis invested at each given rate,
Rate 1 = 4/8.11× 800
= 3200/8.11
= $394.57
Rate 2 = 6/8.11× 800
= 4800/8.11
= $591.86
The amount of money that Phyllis invested at each given rate of 4 and 6 percent is = $394.57 and $591.86 respectively.
Learn more about simple interest here:
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Answer: 298.8 seconds
Step-by-step explanation: 4.98*60=298.8
<span>Formula: H(t) = 56t – 16t^2
</span>
H(t) = - 16t^2 + 56t
<span><span>A.
</span>What is the height of the ball after 1 second? H
(1) = 56(1) – 16(1) ^2 = 40 pt.</span>
<span><span>B.
</span>What is the maximum height? X = - (56)/2(- 16) =
1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.</span>
<span><span>C.
</span><span>After how many seconds will it return to the
ground? – 16t^2 + 56t = 0 - 8t =0 t = 0</span></span>
<span><span>-
</span><span>8t (2 + - 7) = 0 2t – 7 = 0 t = 7/2
Ans: 3.5 seconds</span></span>
It is around 1.81 kilograms
