General form of circle with center at C(a,b) and radius r is
(x-a)^2 + (y-b)^2 = r^2. Here,
(x-(-3))^2 + (y-12)^2 = 5^2, or (x+3)^2 + (y-12)^2 = 25
Answer:
30 and 6
Explanation:
Let the numbers be x and y. Then
<span>x+y=36</span>
<span>x−y=24</span>
Adding the two equations together gives
<span>2x=60</span>
<span>∴x=30</span>
Substituting this back into either of the equations gives <span>y=<span>6</span></span>
The total area of the frame is therefore 2(4x) + 2(4)(x-8) = 8x + 8x - 64 = 16x - 64
The x-intercept is what 'x' is when 'y' is equal to 0. So plug in 0 for 'y' and solve for 'x':


Simplify:

Divide 4 to both sides:

So the x-intercept is (4, 0).
The y-intercept is what 'y' is when 'x' is equal to 0. So plug in 0 for 'x' and solve for 'y':


Simplify:

Divide 2 to both sides:

So the y-intercept is (0, 8).
It would have a variable, and/or coefficients and sometimes constants