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vazorg [7]
3 years ago
8

Hellp me solve this thanks

Mathematics
1 answer:
stellarik [79]3 years ago
4 0

Answer:

c. 10 cm

Step-by-step explanation:

The parallel sides of trapizium are the bases so

base 1(B1) =9cm , base(B2)= 12cm

area(a) = 105 {cm}^{2}

the perpendicular distance means the height so lets find the height

area of trapizium= <u>B1 + B2</u> × h

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>2

{105cm}^{2}(the \: given \: area)  =  \frac{9cm(the \: given \: base) + 12cm(the \: given \: base)}{2}  \times h

{105cm}^{2}  =  \frac{21cm}{2}  \times h

now we crisscross

{105cm}^{2} \times 2 = 21cm \times h

{210cm}^{2}  = 21cm \times h

\frac{ {210cm}^{2} }{21cm}  =  \frac{21cm \: }{21cm}  \times h

h = 10 cm

hope u like it ‍❤️‍‍❤️‍‍❤️‍

For any question comment me

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