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3 years ago

Solve for p. P=? 12 = p 11 12

Mathematics

1 answer:

Mariulka [41]3 years ago

8 0

Answer:

p = 144/11

Step-by-step explanation:

12/11 = p/12

~Simplify

12/11 = 1/12p

~Multiply 12 to both sides

144/11 = p

Best of Luck!

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An ordinary Fair die is a cube with the numbers 1 through 6 on the sides represented by painted spots imagine that such a die is

Hoochie [10]

Answer: Probability of, Event A = 5/18

Event B = 1/2

Step-by-step explanation:

Since, The probability of an event = Number of outcomes of the event/ total number of outcomes.

Since, If a fair dire rolled two times then the total number of outcomes, n(S) = 6 × 6 = 36

And, Event A: The sum is greater than 8.

So, possible outcomes are, ( 3,6), (4,5), (4,6), (5,5), (5,6), (5,4), (6,6), (6,5), (6,4), (6,3)

Thus, n(A) = 10

Since, Probability of event A,

P(A) = n(A)/n(S) = 10/36 = 5/18

Therefore, P(A)= 5/18

Now, Event B: The sum is an even number.

So, possible outcomes are, (1,1),(1,3), (1,5), (2,2), (2,4), (2,6), (3,1), (3,3), (3,5), (4,6), (4,2), (4,4), (5,1), (5,3), (5,5), (6,2), (6,4), (6,6)

Thus, n(B)= 18

Since, Probability of event B,

P(B)= n(B)/n(S) = 18/36 = 1/2

Therefore, P(B)= 1/2

7 0

3 years ago

What is the equation of a line with slope<br> 12 / 2 and a y-intercept of -4 ?

ValentinkaMS [17]

Answer: y= 6x-4

Step-by-step explanation:

I wrote it in y=mx+b format. m is the slope and b is the y-intercept.

The slope is 6 because 12/2=6

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3 years ago

How would you do this algebra question?

sergey [27]

Add then I would divide it

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3 years ago

Read 2 more answers

The average annual premium for automobile insurance in the United States is $1411. A representative sample of annual premiums fo

Harrizon [31]

Using confidence interval concepts, it is found that:

a) The point estimate is the sample mean.

b) The confidence interval is: $\overline{x} \pm T\frac{s}{n}$

c) If $1411 is between the bounds of the interval yes, otherwise no.

--------------

At item a, it asks to provide a point estimate for the population mean, which is the sample mean $\overline{x}$

--------------

Item b:

In the spreadsheet, it is possible to find the <em>standard deviation for the sample</em>, thus, the t-distribution is used.
The confidence interval will be given by:

$\overline{x} \pm T\frac{s}{n}$

In which:

$\overline{x}$ is the sample mean.
T is the critical value, from the t-distribution, with a two-tailed area of $\frac{1 - 0.95}{2} = 0.025$ and n-1 degrees of freedom.
s is the standard deviation for the sample.
n is the sample size.