1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vladimir79 [104]
3 years ago
9

Suppose that only 25% of all drivers come to a complete stop at an intersection having flashing red lights in all directions whe

n no other cars are visible. What is the probability that, of 20 ran- domly chosen drivers coming to an intersection under these conditions, a. At most 6 will come to a complete stop
Mathematics
1 answer:
alukav5142 [94]3 years ago
4 0

Answer:

The probability that at most 6 will come to a complete stop is 0.7857.

Step-by-step explanation:

Let <em>X</em> = number of drivers come to a complete stop at an intersection having flashing red lights in all directions when no other cars are visible.

The probability of the event <em>X</em> is, P (X) = <em>p</em> = 0.25.

The sample of drivers randomly selected is of size, <em>n</em> = 20.

The random variable <em>X</em> follows a binomial distribution with parameters <em>n</em> = 6 and <em>p</em> = 0.25.

The probability function of  Binomial distribution is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,...

Compute the probability that at most 6 will come to a complete stop as follows:

P (X ≤ 6) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3)

                     + P (X = 4) + P (X = 5) + P (X = 6)

   ={20\choose 0}(0.25)^{0}(1-0.25)^{20-0}+{20\choose 1}(0.25)^{1}(1-0.25)^{20-1}+{20\choose 2}(0.25)^{2}(1-0.25)^{20-2}\\...+{20\choose 0}(0.25)^{6}(1-0.25)^{20-6}\\=0.0032+0.0211+0.0669+0.1339+0.1897+0.2023+0.1686\\=0.7857

Thus, the probability that at most 6 will come to a complete stop is 0.7857.

You might be interested in
PLZ PLZ HELP ME WILL GIVE 100 pts ASAP (also brainliest to the user with a better answer
andrezito [222]
Divide the angle into two equal (congruent) parts without actually measuring the angle.
4 0
3 years ago
Read 2 more answers
How do I solve this?
storchak [24]
What you would do, is add up on how many people have is Non-Fiction books and Fiction books. Once you have that, subtract it. You should get an answer of 2.
6 0
3 years ago
Help and explain explain !!!!!!!!!!
tigry1 [53]

Answer:

x=-1\text{ or }x=11

Step-by-step explanation:

For a=|b|, we have two cases:

\begin{cases}a=b,\\a=-b\end{cases}

Therefore, for 18=|15-3x|, we have the following cases:

\begin{cases}18=15-3x,\\18=-(15-3x)\end{cases}

Solving, we have:

\begin{cases}18=15-3x, -3x=3, x=\boxed{-1},\\18=-(15-3x), 18=-15+3x, 33=3x, x=\boxed{11}\end{cases}.

Therefore,

\implies \boxed{x=-1\text{ or }x=11}

3 0
3 years ago
Can someone please answer this for me
djverab [1.8K]

Answer:

C

Step-by-step explanation

the numbers are decreasing -3

4 0
2 years ago
Read 2 more answers
Fill in the blank _+8=+6<br> And chose the property of addition you send
Paha777 [63]

Answer:

-2

Step-by-step explanation:

Just use 6-8 and you will get - 2

Check again with - 2+8 you will get positive 6

4 0
3 years ago
Other questions:
  • Help me!!!! Please!!!!! Math!!!!
    8·1 answer
  • A computer programmer charges $45 an hour for a coding projects plus a start-up fee of $150.
    13·1 answer
  • What is the value of n? 52+23+n=16
    5·2 answers
  • 10 + 2 = 9 + blank i need to know this cause i think its hard
    7·1 answer
  • Expand and simplify 4 (x-3)-2 (1-x)
    8·2 answers
  • Elena runs for 28 seconds and finishes at 250 seconds what is her velocity please explain
    6·1 answer
  • -5(4-n)=1+2n<br> Anyone know this
    11·1 answer
  • PLEASE HELP ILL GIVE BRAINLIEST The graph of y = f(x) is shown below. What are all of the real solutions of f(x) = 0?
    15·2 answers
  • 6. If f(x) = -2r2 + x-5, what is f(3)?
    8·1 answer
  • What does 1/4 of a can of coffee cost if 4 cans of coffee cost $2. 40?.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!