Answer:
a) 29.23% probability that a randomly selected home run was hit to right field
b) 29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes. It is said to be unusual if it is lower than 5% or higher than 95%.
(a) What is the probability that a randomly selected home run was hit to right field?
Desired outcomes:
19 home runs hit to right field
Total outcomes:
65 home runs
19/65 = 0.2923
29.23% probability that a randomly selected home run was hit to right field
(b) Was it unusual for this player to hit a home run to right field?
29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.
Log1715=Log17X
X=Log1715/Log17
X=2,6
Answer:
x = √5 + 4 , -√5 + 4
Step-by-step explanation:
3(x - 4)^2 = 15
/3 /3 (divide both sides by 3)
----------------------
(x - 4)^2 = 5
(x−4)^2⋅1/2 = ±√5 (take square root of both sides)
x - 4 = ±√5 (add 4 on both sides)
+ +4
-----------------
x = √5 + 4 , x = -√5 + 4
23.5
(x^2 +y^3)/ (x+y) = (4^2 +5^3)/(4+2) = 23.5
