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ivanzaharov [21]
3 years ago
10

Triangle RST was dilated by a scale factor of . The image, triangle R'S'T', is an isosceles triangle, with each leg measuring 8

units.
What is the length of a leg of the pre-image, triangle RST?

Mathematics
2 answers:
VMariaS [17]3 years ago
7 0

Answer:

16 ya'll

Step-by-step explanation:

                                                                         

Alik [6]3 years ago
4 0
<span>Triangle RST was dilated by a scale factor of 1/2

Given: </span><span>triangle R'S'T', is an isosceles triangle, with each leg measuring 8 units. 

Pre-image: 
measure of pre-image * scale factor = measure of resulting image

measure of pre-image = measure of resulting image / scale factor

measure of pre-image = 8 / 1/2
measure of pre-image = 8 * 2/1 

measure of pre-image = 16 units.</span>
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Allisa [31]

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4 years ago
The Earth rotates every 24 hr and as diameter of 7, 926 mi. If you're standing on the equator, how fast are you traveling in mil
Vlada [557]
<h3>Answer: Approximately 1038 mph</h3>

The more accurate value is 1037.51097384802

Round that however you need to.

=======================================

Explanation:

We need the circumference of the equator. Think of the equator as the largest possible circle (or belt) to fit around the earth.

C = pi*d

C = pi*7926

C = 7926pi

C = 24,900.2633723527

In 24 hours, a person at the equator travels roughly 24,900.2633723527 miles since the earth does a full rotation in this timespan.

Divide the two quantities distance over time to get the speed

rate = distance/time

rate = (24,900.2633723527 miles)/(24 hours)

rate = ( (24,900.2633723527)/(24) ) miles per hour

rate = 1,037.51097384802

rate = 1038 mph

I'm rounding to 4 sig figs since the diameter is given to be in four sig figs.

This speed of roughly 1038 mph is a linear speed and not an angular speed.

-----------------------------

Extra info (optional section)

Upon further research, I found an article from NASA JPL (jet propulsion laboratory) which states quote:

<em>"To make one complete rotation in 24 hours, a point near the equator of the Earth must move at close to 1000 miles per hour (1600 km/hr)"</em>

Their figure of 1000 mph seems to be a rough estimate, more or less. It's fairly close to the 1038 figure we got earlier.

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