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3 years ago

Factor the greatest common factor 35x^2 +10x^3-20x^2

Mathematics

1 answer:

kupik [55]3 years ago

7 0

35x^2 +10x^3-20x^2 = 5x^2(7 + 2x - 4)

answer
GCF = 5x^2

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Y=-x-3

nadya68 [22]

Answer: Heyaa! :)

1. y=-x-3 = -1

Slope: −1

y-intercept: (0,−3)

2. y=4x-5 = 4

Slope: 4

y-intercept: (0,−5)

3. 2x-y=-2 = 2

Slope: 2

y-intercept: (0,2)

4. x+y=4 = 1

Slope: −1

y-intercept: (0,4)

5. 3x+4y=-12 = - 3/4

Slope: −3/4

y-intercept:

(0,−3)

Hopefully this helps you!

- Matthew

4 0

1 year ago

Mike makes and sells skateboards. If he has a cost of $6,200 per year plus a cost of $15 per skateboard, how many skateboards mu

Roman55 [17]

Answer: 310

Step-by-step explanation:

35-15= 20

6200 / 20 = 310

3 0

2 years ago

Question attached: attached below ||

LenaWriter [7]

Check the picture below

solve for "x"

when taking the sine, make sure your calculator is in Degree mode, since the angle is in degrees, not radians

7 0

3 years ago

Fair rickets for 2 adults and 3 children cost $34. An adult ticket costs $2 more than a child ticket. What is the price of an ad

Studentka2010 [4]

Answer:

Step-by-step explanation:

An adult ticket costs $2 more than a child ticket

Let x and (x + $2)represent the cost of the child and adult ticket respectively

2(x+ $2) + 3x = $34

now solving for x

2x+ $4 + 3x = $34

5x = $30

x = $6 , the cost of the child ticket.

the cost of adult ticket $6+2=$8

3 0

2 years ago

BRAINLIESTTT ASAP! PLEASE HELP ME :)

sergiy2304 [10]

Answer:

$\displaystyle Maximum: 11$

Step-by-step explanation:

Convert this Quadratic Equation to Vertex Form by completing the square, $\displaystyle y = a[x - h]^2 + k$ :

$\displaystyle -5x^2 -10x + 6 \\ \\ -5x^2 - 10x + 25 + k \\ -5[x^2 + 2x - 5] + k \\ -5[x^2 + 2x + 1] + k → -5[x^2 + 2x + 1] + 11 → f(x) = -5[x + 1]^2 + 11 \\ \\ Vertex: [-1, 11]; 11 = Maximum$

So as you can see, each time we broke the equation down, we used the formula $\displaystyle [\frac{b}{2}]^2$ to complete the square.

** In the Vertex Formula, −h gives the OPPOSITE terms of what they really are, so do not forget it.

I am joyous to assist you anytime.

4 0

2 years ago