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exis [7]
3 years ago
14

If jordan made 12 baskets out of 20 attempts,what percent did he score​

Mathematics
1 answer:
anzhelika [568]3 years ago
8 0

Answer:

60%

Step-by-step explanation:

12 divided by 20 is 0.6

you multiply times 100 and you get 60%

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A man flies a kite with a 100 foot string the angle of elevation of the string is 52 how high off the ground is the kite
Slav-nsk [51]
The kite is approximately 78.80 feet off of the ground.


Explanation: If we assume that the string his held taut without any swag, we can use a right triangle to solve for the height of the kite. sin
θ
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100
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4 0
3 years ago
Read 2 more answers
A cylinder has a radius of 3 cm. Sand is poured into the cylinder to form a layer 2 cm deep. What is the volume of sand in the c
netineya [11]

Answer:

Volume=56.54cm³

Step-by-step explanation:

Solution,\\\\Radius(r)=3cm\\\\Height(h)=2cm\\\\Now,\\\\Volume=\pi r^{2} h\\\\Volume=\pi *(3cm)^{2} *2cm\\\\Volume=18\pi cm^{3} =56.54cm^{3}

3 0
2 years ago
There are many toys in a kindergarten. The ratio of the number of dolls to the number of balls to the number of cars is 7:8:5. I
Nina [5.8K]

Answer:

There are 28 dolls, 32 balls,  20 cars   for 80 total toys

Step-by-step explanation:

dolls : balls: cars: total

7           8          5    (7+8+5)

7           8           5        20

We have a total of  80  

80/20 = 4

We need to multiply each number by 4

dolls : balls: cars: total

7*4     8*4     5*4      20*4

28       32      20       80


There are 28 dolls, 32 balls,  20 cars   for 80 total toys

4 0
3 years ago
64,223=_____=641.23<br>​
FrozenT [24]

Answer: Check

12^10 × 12^(-2) = 12^(10 - 2) = 12^8

________________________________

Second option : ---

3^2 × 4^6 = 3^2 × 4^2 × 4^4 = 12^2 × 4^4

________________________________

Third option : ---

(12^8)^0 = 12^(8 × 0) = 12^0 = 1

________________________________

4th option : Check

12^10 / 12^2 = 12^10 × 12^(-2) = 12^(10 - 2)

= 12^8

________________________________

5th option : Check

2^8 × 6^8 = ( 2 × 6 )^8 = 12^8

Step-by-step explanation:

3 0
2 years ago
If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.
nydimaria [60]

Answer:

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}

Step-by-step explanation:

Given

\cos(\theta) = -\frac{2}{3}

\theta \to Quadrant III

Required

Determine \tan(\theta) \cdot \cot(\theta) + \csc(\theta)

We have:

\cos(\theta) = -\frac{2}{3}

We know that:

\sin^2(\theta) + \cos^2(\theta) = 1

This gives:

\sin^2(\theta) + (-\frac{2}{3})^2 = 1

\sin^2(\theta) + (\frac{4}{9}) = 1

Collect like terms

\sin^2(\theta)  = 1 - \frac{4}{9}

Take LCM and solve

\sin^2(\theta)  = \frac{9 -4}{9}

\sin^2(\theta)  = \frac{5}{9}

Take the square roots of both sides

\sin(\theta)  = \±\frac{\sqrt 5}{3}

Sin is negative in quadrant III. So:

\sin(\theta)  = -\frac{\sqrt 5}{3}

Calculate \csc(\theta)

\csc(\theta) = \frac{1}{\sin(\theta)}

We have: \sin(\theta)  = -\frac{\sqrt 5}{3}

So:

\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}

\csc(\theta) = \frac{-3}{\sqrt 5}

Rationalize

\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}

\csc(\theta) = \frac{-3\sqrt 5}{5}

So, we have:

\tan(\theta) \cdot \cot(\theta) + \csc(\theta)

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)

Substitute: \csc(\theta) = \frac{-3\sqrt 5}{5}

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}

Take LCM

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}

6 0
3 years ago
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