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charle [14.2K]
4 years ago
14

Why are seedless vascular plants considered paraphyletic rather than monophyletic?

Biology
1 answer:
iren [92.7K]4 years ago
7 0

Answer:

because they have seeds while others don't

Explanation:

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In humans, aniridia, a type of blindness, is due to a dominant allele A. Migraine headaches are due to another dominant allele M
leonid [27]

Answer:

9/16

Explanation:

This is a typical dihybrid cross involving two genes; one coding for anridia (form of blindness) and the other for Migraine headache, both in humans. The allele for possessing anridia (A) is dominant over the allele for not possessing it (a) in the first gene, while the allele for having Migraine headache (M) is dominant over the allele for not having it (m) in the second gene.

A cross between a man that is heterozygous for both genes (AaMm) and a woman also heterozygous for the two genes (AaMm), this means that both parents are dominant for the two traits i.e. they both possess anridia and migraine headache.

Both parent cells will undergo meiosis to produce four possible combination of gametes in which the alleles are independent of one another in the gametes, according to Mendel's law of independent assortment. The gametes are: AM, Am, aM, am

These gametes are crossed using a punnet square (see attached image) to produce 16 possible offsprings in a phenotypic ratio of 9:3:3:1.

9- Offsprings with both anridia and migraine

3- Offsprings with only anridia but without migraine

3- Offsprings with only migraine but without anridia

1- Offsprings without both anridia and migraine

According to the question, the chance of an offspring expressing both traits i.e. having both anridia and migraine headache is 9/16

4 0
3 years ago
I NEED HELP ON KEY CONCEPT!!
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Phosphofructokinase catalyzes the phosphorylation of fructose 6‑phosphate to fructose 1,6‑bisphosphate in glycolysis. Fructose 1
Airida [17]

Answer:

Fructose 2,6‑bisphosphate (F26BP) activates phosphofructokinase‑1 (PFK -1) and inhibits fructose 1,6‑bisphosphatase (FBPase)

Explanation:

Fructose 2,6‑bisphosphate (F26BP) is a metabolite that is produced with an increase in glucose, hence increasing the availability of fructose-6-phosphate. With, the increased concentration of F26BP, it increases the affinity of PFK- 1 to fructose-6-phosphate, thereby activating glycolysis which enhances the catabolism of glucose. In contrast, F26BP inhibits the activity of  fructose 1,6‑bisphosphatase (FBPase), hence inhibiting gluconeogenesis. Gluconeogenesis (formation of glucose) will not be need since there is the presence of glucose in the system.

In summary, fructose 2,6‑bisphosphate (F26BP) reciprocally controls the enzymatic activity of  phosphofructokinase‑1 (PFK -1) and fructose 1,6‑bisphosphatase (FBPase); it inhibits gluconeogenesis by inhibiting the enzyme, FBPase and activates glycolysis by activating the enzyme PFk -1

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4 years ago
Organic farming is a method of growing food crops with natural alternatives to chemical pesticides. How does organic farming hel
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Because those hazardous waste products do not get into the crops, which we then eat so we would end up spreading them when we defecate, and then other creatures would pass on then feces (the dung beetles), and creatures would eat the beetles(probably coyotes), and then chain would keep on going.

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Which wavelength of light is being reflected by the radish plant?
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