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3 years ago

53 x + 4 < 7 how is this graphed on a number line ?

Mathematics

1 answer:

ValentinkaMS [17]3 years ago

4 0

Answer:

Solve for x first.

54x + 4 < 7

54x < 7 - 4

54x < 3

x < 3 / 54

x < 1/18

So the value is less than 1/18.

To draw on the number line, draw from point 1/18 to the back with an arrow to represent that x is any number less than 1/18.

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student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$

= $(\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5$

= $(\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]$

= $(\frac{3}{4^4})[1+\frac{1}{16}]$

= $(\frac{3}{256})[\frac{17}{16}]$

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0

3 years ago

Rewrite the following equation in slope-intercept form<br> y-6=-9(x-5)

gogolik [260]

Answer:

y=-9x+51

Step-by-step explanation:

-9x+45=y-6

add 6 to both sides to get

-9x +51=y

7 0

3 years ago

Please help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!<br> x = ___

Rzqust [24]

Answer:

Step-by-step explanation:

please help me !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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7 0

3 years ago

Please help me!!! I'm lost tap the attachment

BabaBlast [244]

Answer:

Below.

Step-by-step explanation:

I'll do number 20, 21, 22 for you.

20. It is ±1, ±2, ±4, ±8.

21. Reflected over the x-axis and down 4.

22. Common ratio = 25/5 = 5.

23. Imaginary roots occur in pairs so there is also a root -5i.

The answer is c.

19. Option (a).

This is a translation of 4 to the left ( due to the (x + 4).

3 0

3 years ago

A^2(64a^2-3)/3=27-4a^2/4

frutty [35]

The answer is a = 3/4 = 0.75

First get rid of the paranthesis,
${a}^{2} (64 {a}^{2} - 3) = 64 {a}^{4} - 3 {a}^{2}$
Then set the denominators equal:
$\frac{ 256 {a}^{4} - 12 {a}^{2}}{12} = \frac{81 - 12 {a}^{2} }{12}$
Then remove the denominators and solve:
$256 {a}^{4} - 12 {a}^{2} = 81 - 12 {a}^{2}$
Eliminate -12a^2 by adding 12a^2 to both sides:
$256 {a}^{4} = 81$
Take the fourth root of them or take the square root twice:
$\sqrt[4]{256 {a}^{4} } = \sqrt[4]{81} \\ 4a = 3$
Divide both sides by 4:
$a = \frac{3}{4} = 0.75$

7 0

3 years ago