Sh(2x) = (e^2x + e^-2x)/2
<span>Thus the integral becomes </span>
<span>Int[e^3x*(e^2x + e^-2x)/2] = Int[(e^5x + e^x)/2] </span>
<span>= e^5x/10 + e^x/2 + C
</span>=(1/10)(e^5x) + (1/2)(e^x) + C
heather can do 2 problems in 10 minutes....60 minutes in an hr
2/10 = x / 60...2 problems to 10 min = x problems to 60 min
10x = 120
x = 120/10
x = 12....so she can do 12 problems in 1 hr
Joel can complete 3 problems in 15 minutes...
3/15 = x / 60
15x = 180
x = 180/15
x = 12....so he can do 12 problems in 1 hr
so 24 problems can be done in 1 hr
Heather started with 3 problems done and Joel started with 2 problems done....added = 5 problems already done
and it is asking between 30 and 50 hrs.....so there is no equal sign in ur problem
ur answer is : 30 < 24x + 5 < 50 <==
Let's look at the one that is less than 1/2.
This would be 1/8, so that should go first. We can eliminate B and c.
7/6 is more than 1, so we can eliminate d.
So, A would be the answer.
Which ones do you need help on i’ll try to help you ???
Answer:
1) Ben, 2) 
, 3) 
, 4) 
Step-by-step explanation:
1) Ben has a higher rate of memorization, since the coefficient of the second power is lesser than the one from Alice.
2) The number of words can be estimated by integrating the function:
Alice
Ben
3) The average amount of words per minute is:
4) The average amount of words per minute is:
