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frutty [35]
3 years ago
10

Carloshas1.2 meters of wood if cut into 3 equal pieces how many mm each

Mathematics
1 answer:
sdas [7]3 years ago
5 0
1.2 ÷ 3 = 0.4 meters each 
0.4 meters = 40 cm 
40 cm = 400 mm 

therefore, 
Carlos must cut each piece of wood 400 mm each. 

Hope this helps and have a great day! :D

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You and your friend go to tacos Galore for lunch. You order 3 soft tacos and 4 burritos and your bill comes out to $18.00. Your
Korolek [52]

Answer:

Soft Tacos = 2

Burritos= 3

Step-by-step explanation:

You

3 x 2 = 6

18 - 6 = 12

12/4= 3

You spent 6$ on soft tacos and 12$ on burritos.

Your friend

2 x 2 = 4

10-4 = 6

6/2 = 3

Your friend spent 4$ on soft tacos and 6$ on burritos.

I hope I explained this well.

6 0
3 years ago
What is the LCM of 5, 20, 30, and 35?
Vaselesa [24]
The LCM of 5,20,30,& 35 is 140
8 0
3 years ago
the length of the pool is 5 meters more than it’s width. The area is 24 square root. What is the length of the pool?
Arlecino [84]
The length of the pool is 8 meters. The width of the pool is 3 meters.
8 0
3 years ago
Guys what is the volume formula called for this please ?
alexandr402 [8]

Answer:

Total Area = 24830.437m^{3}

Step-by-step explanation:

This will be using different AREA formula to find the inner area amount

The image is color coded to each shape area

Let me know if you have any questions !

Hope this helps :)

5 0
3 years ago
How to find extreme values of a function.
baherus [9]

Answer:

See below

Step-by-step explanation:

Extreme values of a function are found by taking the first derivative of the function and setting it equal to 0. To determine if it's a minimum or maximum, we set the second derivative equal to 0 and determine if its positive or negative respectively.

Let's do f(x)=3x^4+2x^3-5x^2+7 as an example

By using the power rule where \frac{d}{dx}(x^n)=nx^{n-1}, then f'(x)=12x^3+6x^2-10x

Now set f'(x)=0 and solve for x:

0=12x^3+6x^2-10x

0=2x(6x^2+3x-5)

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-3\pm\sqrt{3^2-4(6)(-5)}}{2(6)}

x=\frac{-3\pm\sqrt{9+120}}{12}

x=\frac{-3\pm\sqrt{129}}{12}

x=-\frac{3}{12}\pm\frac{\sqrt{129}}{12}

x=-\frac{1}{4}\pm\frac{\sqrt{129}}{12}

x_1=0,x_2\approx0.6965,x_3=-1.1965

By plugging our critical points into f(x), we can see that our extreme values are located at (0,7), (0.6965,5.956), and (-1.1965,2.565).

The second derivative would be f''(x)=36x^2+12x-10 and plugging in our critical points will tell us if they are minimums or maximums.

If f''(x)>0, it's a minimum, but if f''(x), it's a maximum.

Since f''(0)=-10 then (0,7) is a local maximum

Since f''(0.6965)=15.822>0, then (0.6965,5.956) is a local minimum

Since f''(-1.1965)=27.18>0, then (-1.1965,2.565) is a global minimum

Therefore, the extreme values of f(x)=3x^4+2x^3-5x^2+7 are a global minimum of (-1.1965,2.565), a local minimum of (0.6965,5.956), and a local maximum of (0,7).

Hope this example helped you understand! I've attached a graph to help you visualize the extreme values and where they're located.

7 0
3 years ago
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