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Ahat [919]
3 years ago
5

A vertical pole is supported by two ropes staked to the ground on opposite sides of the pole. One rope is 8 meters long, and the

other is 7 meters. The distance between the stakes is 6 meters, and the height of the pole is meters.
a3.30
b3.78
c6.17
d6.78
Mathematics
2 answers:
aniked [119]3 years ago
8 0
Establish two right triangles, both with the height of the pole, h.

Call x the distance from the pole to one stake. Then the distance from the other stake to the pole is 6 -x.

Apply Pytagora's equation to both triangles.

1) h^2 = 7^2 - x^2

2) h^2 = 8^2 - (6-x)^2

Eaual 1 to 2

7^2 - x^2 = 8^2 - 6^2 +12x -x^2

12x = 7^2 -8^2 +6^2 = 49 -64 + 36 = 21

x = 1.75

Substitue x-value in 1

h^2 = 49 - (1.75)^2 = 45.94

h = sqrt(45.94) = 6.78

Answer: option d.
BlackZzzverrR [31]3 years ago
3 0
The correct answer is d. 6.78
Here's how to solve this problem in order to get the height of the pole.
Let x = the distance of the 7-m pole to the vertical pole.
Let 6-x = the distance of the 8-m pole to the vertical pole. 

X^2 + h^2 = 7^2 
<span>(6-X)^2 + h^2 = 8^2

x^2 + h^2 = 49
(6-x) + h^2 = 64
----------------------
x^2 - (6-x)^2 = 15
x^2 - (36 - 12x + x^2)  = 15
x^2 - 36 + 12x - x^2 = 15

x = 7/4


</span><span>X^2 + h^2 = 7^2 
</span>(7/4)^2 + h^2 = 49
h^2 = 49 - 3.0625
h = sqrt (45.9375)
h = 6.78

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Zanzabum

Answer:

78.5 ft²

Step-by-step explanation:

In this situation, the dog's 5 ft leash is the radius of the circle that he forms.

So, the radius is 5.

Use the area formula, A = \pir². Plug in 5 as r, and 3.14 as \pi

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3 years ago
PLEASE HELP, BEEN STUCK FOR AN HOUR
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Answer:

Step-by-step explanation:

To sketch a quadratic function we need two things:

1)  Nature of the curve

2) Vertex

3) y-intercept

The completing square form of the quadratic equation is:

y=a(x-h)^2+k

where,

a represents the nature of the graph it can be maximum or minimum , meaning, if a > 0 then minimum(u shaped curve/happy face) and if a < 0 then maximum(n shaped curve/sad face).

h represents the x-coordinate of the vertex.

k represents the y-coordinate of the vertex.

Now if we compare g(x) with our completing square form we get the following:

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When we simply compare the following we get ,

a = 1 , which means a > 0 since 1 is greater than 0 the nature of the curve will be minimum(happy face/u shaped)

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k = 12, which means the y-coordinate of the vertex is 12

Now we have the nature of the curve, we have the vertex now all we need is the y-intercept.

For y-intercept:

For y-intercept meaning at which point will the graph cross the y-axis(0 , y)

For that we expand the formula and turn it into the standard quadratic equation form by using the formula (a - b)^2

y=(x-4)^2+12\\y=((x)^2-2(x)(4)+(4)^2)+12\\y=x^2-8x+16+12\\y=x^2-8x+28\\

now we compare with the standard quadratic form:

y=ax^2+bx+c

here c is the y-intercept and while comparing we can see that c = 28 ,

so the curve cuts the y-axis at (0 , 28)

So we have all the three things that we need to graph our function.

So we just plot the y-intercept , the vertex , and join the dots. Just a tip draw a dotted line on the x-coordinate of the vertex because the vertex point is also called as a turning point where the graph goes in the opposite direction just like a mirror reflection. I attached 2 images you can check them out. One is handmade(i know i suck at drawing but still xD) , one is sketched by online graphing calculator.

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Step-by-step explanation:

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