Question

​ b(1)=−7 b(n)=b(n−1)+12 ​ Find the 4th term in the sequence

Answer 1

4th term = 29

to generate the terms, substitute n = 2, 3, 4 into the rule

noting that b(1) = - 7

b(2) = b(2 - 1) + 12 = b(1) + 12 = -7 + 12 = 5

b(3) = b(3 - 1) + 12 = b(2) + 12 = 5 + 12 = 17

b(4) = b(4 - 1) + 12 = b(3) + 12 = 17 + 12 = 29

Answer 2

Answer:  The 4th term in the sequence is 29 .

Step-by-step explanation:

The given recursive formula for the sequence :

$b(1)=-7\\\\ b(n)=b(n-1)+12$

To find : 4th term

At n=2 , we have

$b(2)=b(1)+12=-7+12=5$   (Second term)

At n=3 , we have

$b(3)=b(2)+12=5+12=17$  (Third term)

At n=4 , we have

$b(4)=b(3)+12=17+12=29$  (Fourth term)

Therefore , the 4th term in the sequence is 29 .