For #10
x=2 w(x)= 5
x=0 w(x)=-9
x=1 w(x)=-1
x=4 w(x)=7
To get these answers, you must use the p(x) table. When x=2, p(x)=6. So you would substitute p(x) for 6 and solve. That would be what you would do for the rest of teh problems.
For #12, the answer would be 5x^2+15x+5
Just mutiply the areas of the out side and inside and subtract them
First one= x=5
second one= x=1/30 or 0.03 or 30^-1
third one= All real numbers or R
fourth one= No solution
Fifth one= All real numbers or R
Sixth one= p=-10/3 or -3 1/3 or -3.3
R is just the symbol for all real numbers. Also know as infinitely many solutions.
Hope this helps ! :) have a good day! Make sure you eat.
Ok, first put in the -2 for each b. That gives:
|-4(-2)-8|+|-1(-(-2))^2|+2(-2)^3
Let's do each section.
The first section is |-4(-2)-8)|
-4 times -2 is 8, minus 8 is 0. The absolute value of 0 is still 0.
Now we move on to |-1(-(-2))^2)|
First we do exponents
-(-2) is 2, and 2^2 is 4. 4 times -1 is -4. The absolute value of -4 is 4
Now the last section, 2(-2)^3
Exponents first: (-2)^3 is -2 * -2 * -2, which is -8.
-8*2=-16.
0+4+(-16)=-12
seperable differential equations will have the form
what you do from here is isolate all the y terms on one side and all the X terms on the other
just divided G(y) to both sides and multiply dx to both sides
then integrate both sides
once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it
In your problem,
so all you need to integrate is
Answer:
You can expect at least 9 of her postcards to arrive within a week
To find that, we multiply the number of postcards by the probability
15 x 0.62 = 9.3
Hope this helps
Good Luck
