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3 years ago

What is the distance from P(2, –5) to the line y = –8? a. –6 b. 3 c. 5 d. 10

1 answer:

hjlf3 years ago

7 0

Plotting that point puts us at a y value of -5 (the y coordinate of the point P). y=-8 is a straight horizontal line through y=-8, so the distance from -5 to -8 is 3. Remember that distance is never negative. Distance is measured using the absolute value of the numbers. So b is your choice.

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Solve the systems of equations using elimination

coldgirl [10]

Answer:

x=1, y=1. (1, 1). The answer is D).

Step-by-step explanation:

3x-5y=-2

4x-7y=-3

--------------

4(3x-5y)=4(-2)

-3(4x-7y)=-3(-3)

------------------------

12x-20y=-8

-12x+21y=9

--------------------

y=1

3x-5(1)=-2

3x-5=-2

3x=-2+5

3x=3

x=3/3

x=1

6 0

3 years ago

Find k, the constant of proportionality, for the data in this table. Then write an equation for the relationship.

VashaNatasha [74]

Answer:

$k=\frac{32}{5}$ , $y=\frac{32}{5}x$

$k=6.4$ , $y=6.4x$

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

Find the value of the constant of proportionality k

take any ordered pair from the data

For x=25, y=160

$k=\frac{y}{x}$

substitute the values of x and y

$k=\frac{160}{25}$

simplify

$k=\frac{32}{5}$

The linear equation is equal to

$y=\frac{32}{5}x$

$y=6.4x$

7 0

3 years ago

I need help and im dumb

Dahasolnce [82]

D he doesn't care about his family well being

6 0

3 years ago

A satellite moves at a speed of 27,950 kilometers per hour. About how much faster is one satellite than the other? Explain how t

Marianna [84]

27,950 k * X Kilometers
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6 0

3 years ago

A boat’s velocity, measured in meters per second, is described by vector b⇀=⟨3,4⟩. In two or more complete sentences explain how

Sedbober [7]

Answer: Velocity is a vector, so it has a magnitude and direction.

Speed is its magnitude, which is obtained from

|〈-3, 4〉 m/s| = √((-3 m/s)² + (4 m/s)²) = √(25 m²/s²) = 5 m/s

Its direction is an angle θ made with the positive horizontal axis, satisfying

tan(θ) = (4 m/s) / (-3 m/s) = -4/3 → θ = arctan(-4/3) + 180°n

where n is any integer. Now you have to consider that the x coordinate is negative and the y coordinate is positive, so 〈-3, 4〉 points into the second quadrant, and we get an angle there for n = 1 of about

θ ≈ 126.87°

Alternatively, you can use the vector 〈1, 0〉 in place of the axis, then compute the angle by relating it to the dot product, so θ is such that

〈-3, 4〉 • 〈1, 0〉 = |〈-3, 4〉| |〈1, 0〉| cos(θ)

(-3)•1 + 4•0 = √((-3)² + 4²) • √(1² + 0²) cos(θ)

-3/5 = cos(θ) → θ = arccos(-3/5) + 360°n

where again, n is any integer, and we get the same solution θ ≈ 126.87° in the second quadrant when n = 0.

Step-by-step explanation:

5 0

2 years ago