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sleet_krkn [62]
3 years ago
9

What is the term for figures used to measures economic performance?

Computers and Technology
1 answer:
sesenic [268]3 years ago
8 0
Gross Domestic Products is a term used to measure economic performance.
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Convert the following numbers. (Please show all steps; no marks will be awarded if no steps are shown) [1.5 x 4 = 6 marks]
katen-ka-za [31]

Answer:

i. 10210212

ii. 100 101 001 in BASE 2

iii. 46.4631

iv. 12.453125

Explanation:

i. Converting to base 10 we get

=  10 x 162 + 13 x 161 + 9 x 160 = 2777

Converting to base 10 we get  =

2777/3 = 925 with remainder 2

925/3 = 308 with remainder 1

308/3 = 102 with remainder 2

102/3 = 34 with remainder 0

34/3 = 11 with remainder 1

11/3 = 3 with remainder 2

3/3 = 1 with remainder 0

1/3 = 0 with remainder 1

Hence the Answer is 10210212

ii. = Octal is taken in pair of 3 bits , Writing binary of each number in 3 bits we get  = 100 101 001 in BASE 2

iii. = 1 x 52 + 2 x 51 + 3 x 50 + 3 x 5-1   = 38.6 in decimal

Converting to Octal we get

38 /8 = 4 with remainder 6

4 /8 = 0 with remainder 4

.6 x 8 =  4.8

.8 x 8 = 6.4

46.4631

iv. = 1x 81 + 4 x 80 + 3 x 8-1 + 5 x 8-2   = 12.453125

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4 0
3 years ago
Suppose that you are asked to modify the Stack class to add a new operation max() that returns the current maximum of the stack
Advocard [28]

Answer:

Following are the code to the given points:

Explanation:

For point 8.1:

public String max()//defining a method max

{

   String maxVal=null;//defining a string variable that holds a value

   for(int x=0;x<n;x++)

   {

       if(maxVal==null || a[i].compareTo(maxVal)>0)//defining if blok to comare the value

       {

           maxVal=a[i];//holding value in maxVal variable

       }

   }

   return maxVal;//return maxVal variable value

}

For point 8.2:

public void push(String item)//defining a method push that accepts item value in a parameter

{

       a[n]=item;//defining an array to hold item value

       if(n==0 || item.compareTo(maxVals[n-1])>0)//use if to comare item value

       {

               maxVals[n]=item;//holding item value in maxVals variable

       }

       else

       {

               maxVals[n]=maxVals[n-1];//decreasing the maxVals value

       }

       n++;//incrementing n value

}

public String pop()//defining a method pop

{

       return a[--n];//use return value

}

public String max()//defining a method max

{

       return maxVals[n-1];//return max value

}

  • In the first point, the max method is declared that compares the string and returns its max value.
  • In the second point, the push, pop, and max method are declared that works with their respective names like insert, remove and find max and after that, they return its value.
7 0
3 years ago
Which access method would be most appropriate if your manager gave you a special cable and told you to use it to configure the s
GrogVix [38]
Console Port Method

Connecting a computer to a Cisco device through the console port requires a special console cable.
8 0
3 years ago
Write the function setKthDigit(n, k, d) that takes three integers -- n, k, and d -- where n is a possibly-negative int, k is a n
liq [111]

Answer:

Explanation:

Let's do this in Python, first we need to convert the number into string in order to break it into a list of character, then we can replace the kth character with d. Finally we join all characters together, convert it to integer then output it

def setKthDigit(n, k, d):

n_string = str(n)

d_char = str(d)

n_char = [c for c in n_string]

n_char[k] = d_char

new_n_string = ''.join(n_char)

return int(new_n_string)

6 0
3 years ago
Linda installed a special pool for the hydrotherapeutic treatment of severe arthritis, as prescribed by her doctor. The cost of
stellarik [79]

Answer:

Linda is entitled to deduction (before any AGI limitations) of $896 in one year of installation of the pool.

Explanation:

Following is explained calculation for deduction (before any AGI limitations) that is Linda entitled to in the year of installation of the pool.

Given that:

Cost of Installing the pool = $22,400

Paid by insurance company = $5,600

So by deducting the price paid by insurance company from total cost the balance becomes:

Balance = $22,400 - $5,600 = $ 16,800

As the pool increased the value of house by $7,840 so we will deduct this amount from balance:

Balance = $ 16,800 - $7,840 = $8,960

As the useful life given for pool is 10 years so we will divide the balance with 10 to obtain the deduction amount for 1 year:

Deduction amount for one year = $8,960/10 = $8,96

Hence $8,96 will be deducted in one year installation.

i hope it will help you!

7 0
3 years ago
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