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MrRissso [65]
3 years ago
10

Express the given expanded numeral as a Hindu-Arabic numeral. (8x102) +(4x10)(2x1)

Mathematics
1 answer:
Marysya12 [62]3 years ago
5 0

Answer:

The Hindu-Arabic numeral form of the given expanded numeral is 842.

Step-by-step explanation:

The given expanded numeral is

(8\times 10^2)+(4\times 10)+(2\times 1)

We need to express the given expanded numeral as a Hindu-Arabic numeral.

According to Hindu-Arabic numeral the given expanded numeral is written as

(8\times 10^2)+(4\times 10)+(2\times 1)=(8\times 100)+(4\times 10)+(2\times 1)

On simplification we get,

(8\times 10^2)+(4\times 10)+(2\times 1)=(800)+(40)+(2)

(8\times 10^2)+(4\times 10)+(2\times 1)=842

Therefore the Hindu-Arabic numeral form of the given expanded numeral is 842.

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No because it would be
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be
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so
if w^2-9w+81 is perfect square, factored form is either
( \sqrt{1}x+ \sqrt{81})^{2} or ( \sqrt{1}x- \sqrt{81})^{2}  aka ( x+9)^{2} or  ( x-9)^{2}
expand them
(x+9)^2=x^2+18x+81, wron middle term

(x-9)^2=x^2-18x+81 wrong

so it is not






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