1. A quadratic equation has the following form: ax²+bx+c.

2. The leading coefficient is the number that is attached to the variable with the highest exponent. Then, the "a" is the leading coefficient of the quadratic equation.

3. The problem says that the leading coefficient is 1 (a=1) and the roots of the quadratic equation are 5 and -3. Then, you have:

(x-5)(x+3)=0

4. When you apply the distributive property, you obtain:

x²+3x-5x-15=0
x²-2x-15=0

5. Therefore, the answer is:

x²-2x-15=0

4 0

3 years ago

PLZ HELP Find the value of x that makes ΔXYZ~PQR

Galina-37 [17]

Answer:

x = 8

Step-by-step explanation:

$\triangle XYZ \sim\triangle PQR... (GIVEN) \\\therefore \frac{XY}{PQ} = \frac{YZ}{QR}.. (csst) \\\therefore \frac{20}{30}= \frac{x+6}{21}\\\therefore \frac{2}{3}= \frac{x+6}{21}\\\therefore \frac{2\times 21}{3}= {x+6}\\\therefore 14= {x+6}\\\therefore 14-6= {x}\\\therefore 8= {x}\\\huge \orange{\boxed {\therefore x = 8}}$

6 0

3 years ago

You have a coupon worth $18.00 off the purchase of a scientific calculator. At the same time the calculator is offered with a 15

olchik [2.2K]

Answer:

well using your equation p - 18 = 0.85p the answer is p = 120

when u apply p = 120 to your equation

(120) - 18 = 0.85(120)

simplify

102 = 102

I hope this helps you

8 0

3 years ago