Answer: $11,000
Explanation:
The solution to this problem is not tedious or complicated
Solution;
Amount is = $110,000
Percentage of down payment is given as = 10%
To get the amount of the down payments we find the 10% of $110,00
10% of $110,000 is = 10÷100
=0.1
We multiply it by the amount which is 0.1×110,000= $ 11,000
Answer:
Business transactions are denominated in foreign currencies.
Explanation:
Foreign exchange can be referred to as the exchange of one country's currency for another currency. The exchange of these currencies occurs in an exchange market known as forex market.
Foreign exchange risk is a financial risk in which changes in the exchange rate may result in the loss of investment value or huge financial breakdown.
The most effective approach to preventing foreign exchange risks is for organizations to make and receive all forms of payment in their own currency.
Spreadsheets are personal application software that includes a wide range of built-in functions for statistical, financial, logical, database, graphics, and date and time calculations. It is an application or program that is designed for analysis, organization and storing of data in a table form. It functions on data that are entered in the cells of a table where the cells can contain numeric or text values. In this program, you can input equations and relate cells in order to do automatic calculation. It helps in processing a large number of data since you can easily copy and execute functions and equations.
Answer:
the gross pay of Lloyd is $6,250
Explanation:
The computation of the gross pay is shown below:
= Amount received annually ÷ number of months
= $150,000 ÷ 24
= $6,250
Hence, the gross pay of Lloyd is $6,250
we simply applied the above formula so that the correct value could come
The other things would be irrelavant
Answer:
Explanation:
Block on the table m(A) = m1,
block on the cord m2,
the coefficient of static friction is k1=0.4,
the coefficient of kinetic friction is k2 =0.28
(a)
Block A:
T = F(fr) = k1 •N = k(s) • m1 •g,
Block B: T = m2•g.
k1 • m1 •g= m2•g,
m1 = m2/k(s) = m2/0.4.
(b)
Block A:
T = F(fr) = k2 •N = k2 • m1 •g,
Block B:
T = m2•g.
k2• m1 •g= m2•g,
m1 = m2/k2 = m2/0.28.