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Dahasolnce [82]
3 years ago
13

What should I prepare for international mathematical Olympiad?

Mathematics
1 answer:
attashe74 [19]3 years ago
5 0

Answer:

How Do You Qualify for Math Olympiad?

Step 1: Take the AMC 10 or AMC 12. ...

Step 2: Take the AIME. ...

Step 3: Qualify for and Compete in Math Olympiad. ...

#1: Use Quality Practice Problems. ...

#2: Don't Lounge Around. ...

#3: Focus on Your Weak Areas. ...

#4: Beware of Tiny Mistakes. ...

#5: Schedule Regular Study Time.

hope this helps

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John has to pay $50 for three months

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A company that produces fine crystal knows from experience that 17% of its goblets have cosmetic flaws and must be classified as
Alex73 [517]

Answer:

0.3891 = 38.91% probability that only one is a second

Step-by-step explanation:

For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

17% of its goblets have cosmetic flaws and must be classified as "seconds."

This means that p = 0.17

Among seven randomly selected goblets, how likely is it that only one is a second

This is P(X = 1) when n = 7. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{7,1}.(0.17)^{1}.(0.83)^{6} = 0.3891

0.3891 = 38.91% probability that only one is a second

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1

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