Find the value of x is this problem

PLEASE HELP ASAP!!!!!!!!<br> A<br> B<br> C<br> D

AlladinOne [14]

The graph that represents the function is graph b. Graph b is the only graph the appropriately represents the y intercept (the value of y when x = 0).

8 0

3 years ago

How many gallons of gas is in my tank?

weqwewe [10]

F(180) = x/30

= 180/30 = 6 gallons of gas is needed

5 0

3 years ago

In the figure below, the value of x is:<br> who ever show works gets brainlly

blondinia [14]

Answer:

d) x = 72°

Step-by-step explanation:

Corresponding Angles: The pair of angles formed on the same side of traversal which crosses two parallel lines is called a pair of corresponding angles.

These angles are EQUAL to each other.

Now, here in the given figure:

The two below lines are parallel to each other.

Also, the line crossing it on the right side forms a traversal.

So angle x and angle with 72 degrees form a pair of Corresponding Angles.

⇒ x = 72°

Hence the measure of angle x = 72°

7 0

3 years ago

How to do divisibility tables

zhannawk [14.2K]

What's a divisability table are you. B or a g how old

3 0

3 years ago

Arrange the circles (represented by their equations in general form) in ascending order of their radius lengths. X2 y2 − 2x 2y −

Colt1911 [192]

Circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

<h3>What is the equation of circle?</h3>

The equation of the circle is the equation which is used to represent the circle in the algebraic equation form with the value of center point in the coordinate plane and measure of radius.

The standard form of the equation of the circle can be given as,

$(x-h)^2+(y-k)^2=r^2$

Here (h,k) is the center of the circle and (r) is the radius of the circle.

Lets arrange the first equation, in standard form of equation of circle as,

$x^2 +y^2 - 2x+ 2y -1 = 0 \\(x^2 - 2x) +(y^2+ 2y )= 1\\(x^2 - 2x+1) +(y^2+ 2y +1)= 1+1+1\\(x-1)^2+(y+1)^2=(\sqrt{3})^2$

The radius of this circle is √(3).

Lets arrange the second equation, in standard form of equation of circle as,

$x^2 +y^2 - 4x+ 4y - 10 = 0 \\(x^2 - 4x) +(y^2+ 4y )= 10\\(x^2 - 4x+4) +(y^2+ 4y +4)= 10+4+4\\(x-2)^2+(y+2)^2=(\sqrt{18})^2$

The radius of this circle is √(18).

Lets arrange the third equation, in standard form of equation of circle as,

$x^2 +y^2 - 8x - 6y - 20 = 0 \\(x^2 - 8x) +(y^2-6y )= 20\\(x^2 - 8x+16) +(y^2- 6y +9)= 10+16+9\\(x-4)^2+(y-3)^2=(\sqrt{45})^2$

The radius of this circle is √(45).

Similarly, radius of the forth, fifth, sixth and seventh circle is √(23), √(5), √(117) and √(46) units.

Hence, the circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

Learn more about the equation of circle here;

brainly.com/question/1506955

3 0

2 years ago

Read 2 more answers