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astra-53 [7]
3 years ago
14

In IJK, the measure of K=90°, KI = 8.1 feet, and JK = 1.9 feet. Find the measure of

Mathematics
1 answer:
Alborosie3 years ago
8 0

Answer:

77

Step-by-step explanation:

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The bar diagram represents 24 hours in one day and shows a mark at 30%If you sleep 30% of the day, how many hours do you sleep?
horrorfan [7]

Let:

100%---------------->24h

30%------------------>xh

Using cross multiplication:

\begin{gathered} \frac{100}{30}=\frac{24}{x} \\ solve_{\text{ }}for_{\text{ }}x\colon \\ x=\frac{30\cdot24}{100} \\ x=\frac{720}{100}=7.2h \end{gathered}

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1 year ago
Is x + y = 18 linear or non linear?
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A linear equation has 1 for all exponents on the placeholders
aka the equation is first degree (aka the hightest exponent on placeholders=1) so
it is linear
7 0
2 years ago
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Please help and show work thank you!
MariettaO [177]

Answer:

1)-0.65    2) 28.8   3) 747.6

Step-by-step explanation:

  1. divide the numerator (-13) and the denominator (20)
  2. 32 x 90= 2880, divide 2880 by 100 equals to 28.8

    3. multiply 12 by 62.3

I hope this helps!

7 0
2 years ago
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Mark, Jordan and Alex was playing basketball. Mark scored 22 points. Alex scored 16 points. Jordan scored 3 times as much as Mar
dsp73

check image for explanation

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3 years ago
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Plzz help me solve questions 15 and 16...!!
iVinArrow [24]

15.

We have right triangles, with the ladder the hypotenuse of both and the wall the opposite side of both.

Call the ladder length <em>h.</em>

Against the wall we have the opposite of alpha the taller one:

q = h \sin \alpha - h \sin \beta

On the ground adjacent to beta is the longer one

p = h \cos \beta - h \cos \alpha

Dividing

\dfrac p q = \dfrac{  h \cos \beta - h \cos \alpha }{h \sin \alpha - h \sin \beta} =  \dfrac{ \cos \beta -\cos \alpha }{\sin \alpha - \sin \beta} \quad\checkmark

16.

Again I'm too lazy to draw the figure but you should.

Let's call <em>y </em>the height of the tower and <em>x</em> the distance from the observation point on the ground to the base of the tower.

\tan 60^\circ = \dfrac y x

\tan 30^\circ = \dfrac{y - 40}{x}

Since \sin 30 =\cos 60 = \frac 1 2 \textrm{ and } \cos 30 = \sin 60 = \sqrt{3}/2

\tan 60^\circ = \sqrt{3} = y/x

\tan 30^\circ = 1/\sqrt{3} = (y-40)/x

Dividing,

\sqrt{3}/ (1/\sqrt{3}) = (y/x) / ((y-40)/x)

3 = y/(y-40)

3y - 120 = y

2y = 120

y = 60

x = y/\sqrt{3} = 60(\sqrt{3}/3) = 20 \sqrt{3}

Answer: Height 60 meters, distance 20√3 meters

5 0
3 years ago
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