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LenaWriter [7]
3 years ago
12

View attached image.......

Mathematics
2 answers:
NARA [144]3 years ago
5 0
C
this is because if you multiply 5x3 your gonna get 15. 5x2 is 10 10/2 is 5 . hope this helps :).
katrin2010 [14]3 years ago
3 0

Answer:

5^5/6 (The first one)

Step-by-step explanation:

sqrt(5) can be written as 5^1/2

cubert(5) can be written as 5^1/3

Rewrite:

5^1/2 * 5^1/3

According to exponent rules, when multiplying with the same base, add the exponents

1/2 + 1/3 = 5/6

Answer: 5^5/6

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Welp here bro : If you do the equation and the solution is -2 then the student is right

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If a quadrilateral has exactly 2 lines of symmetry and both are angle bisectors then which statement would be true
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If a quadrilateral has exactly 2 lines of symmetry and both are angle bisectors then the figure must be a rhombus because it has exactly 2 pairs of congruent angles.

I hope this helps! :)
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4 years ago
For the given functions, (a) express dw/dt as a function of t, both by using the chain rule and by expressing w in terms of t an
ch4aika [34]

By the chain rule,

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}

We have

w=7ye^x-\ln z\implies\begin{cases}\dfrac{\partial w}{\partial x}=7ye^x\\\\\dfrac{\partial w}{\partial y}=7e^x\\\\\dfrac{\partial w}{\partial z}=-\dfrac1z\end{cases}

and

\begin{cases}x=\ln(t^2+1)\\y=\tan^{-1}t\\z=e^t\end{cases}\implies\begin{cases}\dfrac{\mathrm dx}{\mathrm dt}=\dfrac{2t}{t^2+1}\\\\\dfrac{\mathrm dy}{\mathrm dt}=\dfrac1{t^2+1}\\\\\dfrac{\mathrm dz}{\mathrm dt}=e^t\end{cases}

Putting everything together, we get

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{14ye^xt}{t^2+1}+\dfrac{7e^x}{t^2+1}-\dfrac{e^t}z

x=\ln(t^2+1), so e^x=e^{\ln(t^2+1)}=t^2+1, and z=e^t, so \frac{e^t}z=1.

\dfrac{\mathrm dw}{\mathrm dt}=14yt+7-1

\dfrac{\mathrm dw}{\mathrm dt}=14t\tan^{-1}t+6

Then when t=1, the derivative has a value of \frac{7\pi}2+6.

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3 years ago
A stadium has 20,000 reserved seats and 25,000 general admission seats. If reserved seats are $17.50 and general admission seats
Radda [10]

Answer:

The answer is D. $618,750.

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20,000 x 17.50 = 350,000.

25,000 x 10.75 = 268,750.

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