Answer:
46 cm
Step-by-step explanation:
Let p represent the length in cm of 1 bap'ai; let k represent the length in cm of 1 bok'ai. Then we have ...
12p +2k = 100
10p +10k = 100
Subtracting the second equation from 5 times the first, we get ...
5(12p +2k) -(10p +10k) = 5(100) -(100)
50p = 400
p = 8 . . . . cm
Then the second equation tells us ...
10(8) +10k = 100
10k = 20
k = 2 . . . . cm
Then 5p+3k = 5(8) +3(2) = 46 cm.
The distance 5 bap'ai and 3 bok'ai is 46 cm.
Answer:
Radius r=0.30m, Velocity, v=36m/s
(a) angular speed w=
r
v
=
0.3
36
=120rad/s
(b) final angular speed w
′
=0
From rotational kinematics w
′
2
−w
2
=2αθ
0−14400=2α×40×2π
⇒α=
160π
−14400
=−28.6rad/s
2
'Distance covered
=40×2πr
=40×2π×0.3=75.39m
Answer:
B. x<27
Step-by-step explanation:
300-165=135
135/5=27
The answer to Cindyelias82 question is 5.65685425i
Square Root (-2)+Square Root(-18)=5.65685425i
