Answer:
In the table, we can see values of x and y, to complete it, we just need to input the different values of x in the equation:
y = 16*x^2
For example in the first slot, we have x = -4
Then we will have:
y = 16*(-4)^2 = 240
Then we complete the empty slot with 240.
The table would be:
Now we just need to do the same for the other values:
y(-3) = 16*(-3)^2 = 144
y(-2.5) = 16*(-2.5)^2 = 100
y(-2) = 16*(-2)^2 = 64
y(-1.5) = 16*(-1.5)^2 = 36
y(-1) = 16*(-1)^2 = 16
y(-0.5) = 16*(-0.5)^2 = 4
y(0) = 16*(0)^2 = 0
y(0.5) = 16*(0.5)^2 = 4
y(1) = 16*(1)^2 = 16
y(1.5) = 16*(1.5)^2 = 36
y(2) = 16*(2)^2 = 64
y(2.5) = 16*(2.5)^2 = 100
y(3) = 16*(3)^2 = 144
y(4) = 16*(4)^2 = 240
Then the complete table is:
Then we can see that there is a symmetry around the value x = 0.
That is a very good question....
Look Grank
you know that:
confidence interval = mean +or- Margin of Error
and
Margin of Error = (z)*(standard deviation) / (sqrt of n)
where n is the number of sample records
So we need to calculate z-value firstly
It says: "<span>we want 90% confidence"
So that:
</span>
<span>confidence90% corresponds to z-value of 1.645
Plug that into our formula of </span><span>Margin of Error:
</span>Margin of Error = (1.645)*(22) / (sqrt of n)
"The sample mean is within 2.7 lb of the population mean" means that Margin of Error is 2.7
<span>Margin of Error:
</span>2.7 = (1.645)*(22) / (sqrt of n)
Now solve for n:
n=179.66~180
SO that 180<span> women must be randomly selected to estimate the mean weight of women in one age group.</span>
I think its c because of the question