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Xelga [282]
3 years ago
14

Solve for x, y, and z

Mathematics
1 answer:
valentina_108 [34]3 years ago
4 0

Answer:

bmjbn

Step-by-step explanation:

You might be interested in
2(x+3)^(2)+8=0 Solve.
olga2289 [7]

Answer:

2i-3

Step-by-step explanation:

2(x+3)²=-8

(x+3)²=-4

x+3=2i

x=2i-3

7 0
2 years ago
I'm so confused. Please help I tried the first time got 50 some thing then 33 then 20.25. How do I do this?
vazorg [7]

Answer:

Basically, you have to think: more bricks : more time

more workers : less time

2,400 bricks 6 workers takes 18 hours

You now have to solve for 4,500 blocks and 10 workers

4,500 / 2,400 = 1.875 (times greater)

10 / 6 = 1.666666666 (times less)

So, we get 18 hours, multiply it by 1.875 and divide it by 1.666666666

which equals 20.25 hours

So, it seems you were correct on your third try.


Step-by-step explanation:


5 0
2 years ago
Simplify. Assume that letters represent any real number.
TiliK225 [7]
\sqrt[5]{x^5}=x\\\\32^\frac{3}{5}=\left(32^\frac{1}{5}\right)^3=\left(\sqrt[5]{32}\right)^3=2^3=8
7 0
3 years ago
Read 2 more answers
How to find angle of x in angles
rodikova [14]

Answer:

By using the one the straight line degrees if your doing it for a circle or 180 degrees for a triangle.

6 0
3 years ago
Read 2 more answers
Which of the following in an identity?
sammy [17]
By "which is an identity" they just mean "which trigonometric equation is true?"

What you have to do is take one of these and sort it out to an identity you know is true, or...

*FYI: You can always test identites like this:
Use the short angle of a 3-4-5 triangle, which would have these trig ratios:
sinx = 3/5    cscx = 5/3
cosx = 4/5   secx = 5/4
tanx = 4/3    cotx = 3/4
Then just plug them in and see if it works. If it doesn't, it can't be an identity!

Let's start with c, just because it seems obvious.
The Pythagorean identity states that sin²x + cos²x = 1, so this same statement with a minus is obviously not true.

Next would be d. csc²x + cot²x = 1 is not true because of a similar Pythagorean identity 1 + cot²x = csc²x. (if you need help remembering these identites, do yourslef a favor and search up the Magic Hexagon.)

Next is b. Here we have (cscx + cotx)² = 1. Let's take the square root of each side...cscx + cotx = 1. Now you should be able to see why this can't work as a Pythagorean Identity. There's always that test we can do for verification...5/3 + 3/4 ≠ 1, nor is (5/3 +  3/4)².

By process of elimination, a must be true. You can test w/ our example ratios:
sin²xsec²x+1 = tan²xcsc²x
(3/5)²(5/4)²+1 = (4/5)²(5/3)²
(9/25)(25/16)+1 = (16/25)(25/9)
(225/400)+1 = (400/225)
(9/16)+1 = (16/9)
(81/144)+1 = (256/144)
(81/144)+(144/144) = (256/144)
(256/144) = (256/144)
5 0
2 years ago
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