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Liula [17]
3 years ago
8

Contrast the location of genetic material in bacterial cells to its location in plant and animal cells

Biology
1 answer:
Elodia [21]3 years ago
8 0
In animal and plant cells genetic information if contained within a nucleus, in bacterial cells there is no nucleus and so the genetic information is found within the cytoplasm of the cell but is not 'contained' in a more specific area. A small amount of DNA in the bacterial cell may be contained in an area of the bacteria called a plasmid, however not all bacterial cells have a plasmid. 
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The answer is <span>D) transports fluids throughout the plant.</span>
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Natural selection is the process by which favorable traits tend to increase in frequency over time.
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Answer: The statement is true

Explanation:

Natural selection, as its name implies refers to the choice of certain favorable traits such as resistance to diseases, bigger fruit size etc above lesser favorable traits such as easy susceptibility to diseases, small fruit size etc.

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Thus, the statement is true

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Look at the diagram of the food web. A decrease in the number of willow trees will MOST LIKELY affect which organism in the
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Question: Review the images and text about stages 13 (about 32 days) and 23 (about 53-58 days), and compare the limb development
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n stage 13, all four limb buds are present. In stage 13, the upper limb buds resemble flippers. In stage 23, the upper limb shows well-formed arm, elbow, wrist, and fingers. In stage 23, the lower limb shows well-formed toes, feet, and knees.

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6 0
3 years ago
While alive, an organism absorbs (radioactive) carbon 14 at such a rate that the proportion of carbon 14 in the organism remains
Inga [223]

Answer:

The person has been dead for approximately 15,300 years

Explanation:

<u>Available data</u>:

  • The half-life of carbon 14 is 5,600 years
  • The human skeleton level of carbon 14 is 15% that of a living human

To answer this question we can make use of the following equation

Ln (C14T₁/C14 T₀) = - λ T₁

Where,

  • C14 T₀ ⇒ Amount of carbon in a living body at time 0 = 100%
  • C14T₁ ⇒ Amount of carbon in the dead body at time 1 = 15%
  • λ ⇒ radioactive decay constant = (Ln2)/T₀,₅
  • T₀,₅ ⇒ The half-life of carbon 14 = 5600 years
  • T₀ = 0
  • T₁ = ???

Let us first calculate the radioactive decay constant.

λ = (Ln2)/T₀,₅

λ = 0.693/5600

λ = 0.000123

Now, let us calculate the first term in the equation

Ln (C14T₁/C14 T₀) = Ln (15%/100%) = Ln 0.15 = - 1.89

Finally, let us replace the terms, clear the equation, and calculate the value of T₁.

Ln (C14T₁/C14 T₀) = - λ T₁

- 1.89 = - 0.000123 x T₁

T₁ = - 1.89 / - 0.000123

T₁ = 15,365 years

The person has been dead for approximately 15,300 years

4 0
3 years ago
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