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3 years ago

Is 5-5 a zero or 5+(-5)?

Mathematics

2 answers:

Olenka [21]3 years ago

8 0

5-5 is your answer
hope this helps!

seropon [69]3 years ago

5 0

5-5 is equivalent to 5+(-5), they both equal zero.

You are getting the sum of opposite magnitudes either way :)

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A number, added to its three quarters, is equal to its double decreased by 6. What is the number

faust18 [17]

Answer:

Step-by-step explanation:

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7 0

3 years ago

A study of the relationship between age and various visual functions (such as acuity and depth perception) reported the followin

maks197457 [2]

Answer:

(a) $\sum x_i=56.68$ and $\sum x_i^2=197.46$

(b) The sample variance is $s^2=0.530$ and the sample standard deviation is $s=0.728$

Step-by-step explanation:

(a)

The sum of these 17 sample observations is

$\sum x_i=2.79\:+2.57+\:2.73\:+3.75\:+2.27+\:2.75+\:4.00+\:4.22+\:3.88+\:4.35+\:3.41+\:4.57+\:2.38+\:3.73\:+2.75+\:3.47+\:3.06\\\\\sum x_i=56.68$

and the sum of their squares is

$\sum x_i^2=2.79^2\:+2.57^2+\:2.73^2\:+3.75^2\:+2.27^2+\:2.75^2+\:4.00^2+\:4.22^2+\:3.88^2+\:4.35^2+\:3.41^2+\:4.57^2+\:2.38^2+\:3.73^2\:+2.75^2+\:3.47^2+\:3.06^2\\\\\sum x_i^2=197.46$

(b)

The sample variance, denoted by $s^2$ , is given by

$s^2=\frac{S_{xx}}{n-1}$

where $S_{xx} =\sum x_i^2-\frac{(\sum x_i)^2}{n}$

Applying the above formula we get that

$S_{xx}=197.46-\frac{(56.68)^2}{17}\\\\S_{xx} =8.482$

$s^2=\frac{8.482}{17-1}=0.530$

The sample standard deviation, denoted by s, is the (positive) square root of the variance:

$s=\sqrt{s^2}$

Applying the above formula we get that

$s=\sqrt{0.530}=0.728$

3 0

3 years ago

Hey guys ! Can anyone help me with these problems please and thanks

AnnyKZ [126]

m = 3√2√2

= 6

n = a

= 3√2

Answer =  D) m = 6 , n = 3√2

m = n = a

m = 3

n = 3

Answer = A

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Answer:

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