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damaskus [11]
3 years ago
14

Avi is 4 years older than twice the age of his sister sharda. Avi is 16. how old is sharda a.4yrs b. 6yrs c. 8yrs

Mathematics
2 answers:
lapo4ka [179]3 years ago
6 0

Answer:

B. 6 years old

Step-by-step explanation:

If Avi is 16 and he is 4 years older than twice the age of Sharda then we should minus 4 from 16 first.

1. 16 - 4 = 12

Then divide by two since his age is 4 years older than twice her age.

2. 12 divided by 2 = 6

So 6 is the answer.

MrRissso [65]3 years ago
4 0

Answer:

8 years oldbecouse twice the age of his sister sharda

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Consider a sequence whose first three
snow_tiger [21]

Answer:

Below, depends if 27 is term number 1 or term number 0.  Answered for both cases.  

Step-by-step explanation:

The most common sequences are arithmetic and geometric, so lets check those first.

Arithmetic first since its the easiest.

to go from 27 to 21 we subtract 6, if we subtract 6 from 21 again we get to 15, which is what we need, so it is indeed arithmetic.

Explicit formula is basically of the form of y=mx+b with an arithmetic sequence.  the m is the common difference and b is the first term minus the common difference.  so lets fill those in.  y = -6x + 33

Then it usually has n as the x and y f(n) so we'll just put those in

f(n) = -6n + 33

This si as long as the first term is labeled as term number 1 and not term number 0.  if you have 27 as term 0 instead just make 33 back to 27, so f(n) = -6n + 27

Let me know if this doesn't make sense.

5 0
3 years ago
To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data
nexus9112 [7]

Answer:

a) \sigma = 0.167

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of \mu. So X - \mu = 0.5 must have Z = 3 and X - \mu = -0.5 must have Z = -3.

So

Z = \frac{X - \mu}{\sigma}

3 = \frac{0.5}{\sigma}

3\sigma = 0.5

\sigma = \frac{0.5}{3}

\sigma = 0.167

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that \sigma = 2.8

The standard deviation of a sample of n young man is given by the following formula

s = \frac{\sigma}{\sqrt{n}}

We want to have s = 0.167

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0.167\sqrt{n} = 2.8

\sqrt{n} = \frac{2.8}{0.167}

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6 0
3 years ago
I need help finding the angles. The answer Isn't even
mart [117]

The 3 inside angles of a triangle equal 180.

Add the 3 angles together to equal 180:


X + (5x-20) + 4x = 180

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10x = 200

Divide both sides by 10:

x = 20


Angle A = x = 20

Angle B = 4X = 4(20) = 80

Angle C = 5x-20 = 5(20) -20 = 100-20 = 80

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bezimeni [28]

Answer:

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