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Ostrovityanka [42]
2 years ago
8

I need help with finding x ANSWER ASAP!!!!!!!!!!

Mathematics
1 answer:
arsen [322]2 years ago
3 0

The value of x is 36.

Solution:

Given angles of a triangle are 2x°, 2x° and x°.

To find the value of x:

<em>Sum of the all the angles of a triangle = 180°</em>

2x° + 2x° + x° = 180°

5x° = 180°

Divide by 5 on both sides of the equation.

x° = 36°

x = 36

The value of x is 36.

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yes but it depends on how many friends are in the friend group

8 0
2 years ago
PLEASE HELP ME ON THIS
Dmitry [639]
The domain of the function is 80 to 180 because domain refers to the valid inputs of the function.

After receiving $42, the new domain (<em>that Albert can afford)</em> is from 80 to 147. 


4 0
3 years ago
A sinusoidal function whose period is 4π, maximum value is 6, and minimum value is -2 has a y intercept of 6. What is the equati
IRINA_888 [86]

Equation of the function: f(x) = 4 sin (x/2) + 6.

<h3>What is sinusoidal function ?</h3>

The term sinusoidal is used to describe a curve, referred to as a sine wave or a sinusoid, that exhibits smooth, periodic oscillation. It is named based on the function y=sin(x).

Given: max value= 6, min value= -2, y-intercept= 6.

As, standard form f(x) = A sin (ωx +φ) + k,

where A is the amplitude, ω is the angular velocity with ω=2πf.

Now,

A = |6- (-2)/2|

A = |6 +2/2| = 8/2

A = 4

Also, ω:

The period of a sinusoidal is T = 1/f

so, f = 1 / T

ω = 2πf

ω = 2π ( 1/T) with T = 4π

ω = 2π (1/(4π) = 2π (2)

ω = 1/2

The y-intercept k = 6

So, equation with values A =4, ω = 1/2, k = 6, φ = 0.

f(x) = A f(x)

f(x) = A sin (ωx +φ) + k

f(x) = 4 sin (x/2) + 6.

Hence, equation of the function f(x) = 4 sin (x/2) + 6.

Learn more about this concept here:

brainly.com/question/26315885

#SPJ1

4 0
2 years ago
Please help me please please please
algol13

Answer:

20

Step-by-step explanation:

The lower quartile Q₁ is the value at the left side of the box, that is

Q₁ = 20

5 0
3 years ago
Read 2 more answers
What is c=2pi r for r eqaul to?
drek231 [11]
I hope this helps you

7 0
3 years ago
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