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Ostrovityanka [42]
3 years ago
8

I need help with finding x ANSWER ASAP!!!!!!!!!!

Mathematics
1 answer:
arsen [322]3 years ago
3 0

The value of x is 36.

Solution:

Given angles of a triangle are 2x°, 2x° and x°.

To find the value of x:

<em>Sum of the all the angles of a triangle = 180°</em>

2x° + 2x° + x° = 180°

5x° = 180°

Divide by 5 on both sides of the equation.

x° = 36°

x = 36

The value of x is 36.

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The answer is 222. 20 divided by 1 is 20 so if you divide 4440 by 20 you get 222.


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Which equation represents a linear function That is shown on the graph below?
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A running group has 38 members. Each group member completed half marathon (13.1 miles). The average time to complete is 110 minu
Vikki [24]

Answer:

They took 4,180 minutes total to complete the course.

Step-by-step explanation:

The average time is given by the sum of each individual time of the members divided by the number of members on the group. So if we want to know the total time they took to complete the course we need to take the average and multiply it by the number of people in the group. So we have:

total time = average*number of members = 110*38 = 4180 minutes

They took 4,180 minutes total to complete the course.

8 0
3 years ago
Coach Evans recorded the height, in inches of each player on his team. The results are shown.
marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile (Q_1)

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile (Q_3)

Terms in arranged in ascending order:

57,60,60,61,62,62,63,63,64

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

Q_1 is median of terms 57,60,60,61

Number of terms (n) = 4

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60

So, Q_1=60

So, 25% of the heights of a team is less than 60 inches

Q_3 is the median of terms 62,63,63,64

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63

So, Q_3=63

So, 75% of the heights of a team is less than 63 inches

Interquartile range = Q_3-Q_1=63-60=3

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0
3 years ago
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