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Dafna1 [17]
3 years ago
11

1. Find the product (13 – x2)(x + 2). -x3 - 2x2 + 13x + 26

Mathematics
1 answer:
Eduardwww [97]3 years ago
3 0

Answer:

The product is -x³ - 2x² + 13x + 26

Step-by-step explanation:

* Lets revise how to find the product of two binomials

- If (ax ± b) and (cx ± d) are two binomials, where a , b , c , d are constant

 their product is:

# Multiply (ax) by (cx) ⇒ 1st term in the 1st binomial and 1st term in the

  2nd binomial

# Multiply (ax) by (d) ⇒ 1st term in 1st binomial and 2nd term in

  2nd binomial

# Multiply (b) by (cx) ⇒ 2nd term in 1st binomial and 1st term in

  2nd binomial

# Multiply (b) by (d) ⇒ 2nd term in 1st binomial and 2nd term in

  2nd binomial

# (ax ± b)(cx ± d) = cx² ± adx ± bcx ± bd

- Add the terms adx and bcx because they are like terms

* Now lets solve the problem

- There are two binomials (13 - x²) and (x + 2)

- We can find their product by the way above

∵ (13)(x) = 13x ⇒ 1st term in the 1st binomial and 1st term in the

  2nd binomial

∵ (13)(2) = 26 ⇒ 1st term in 1st binomial and 2nd term in

  2nd binomial

∵ (-x²)(x) = -x³ ⇒ 2nd term in 1st binomial and 1st term in

  2nd binomial

∵ (-x²)(2) = -2x² ⇒ 2nd term in 1st binomial and 2nd term in

  2nd binomial

∴ The product of (13 - x²)(x + 2) = 13x + 26 - x³ - 2x²

- There is no like terms

- Lets arrange the terms from greatest power to smallest power

∴ The product is -x³ - 2x² + 13x + 26

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Answer:

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Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

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___

You seem to have ...

  \dfrac{2^5\times8^4}{16}=\dfrac{2^5\times(2^3)^4}{2^4}\qquad (a=3)\\\\=\dfrac{2^5\times2^{3\cdot4}}{2^4}=\dfrac{2^5\times2^{12}}{2^4}\qquad (b=12)\\\\=2^{5+12-4}=2^{13}\qquad(c=13)

_____

<em>Additional comment</em>

I find it easy to remember the rules of exponents by remembering that <em>an exponent signifies repeated multiplication</em>. It tells you how many times the base is a factor in the product.

  2\cdot2\cdot2 = 2^3\qquad\text{2 is a factor 3 times}

Multiplication increases the number of times the base is a factor.

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Similarly, division cancels factors from numerator and denominator, so decreases the number of times the base is a factor.

  \dfrac{(2\cdot2\cdot2)}{(2\cdot2)}=2\\\\\dfrac{2^3}{2^2}=2^{3-2}=2^1

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Answer:

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Step-by-step explanation:

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