Find the zeros of x3 +2X^2-23x-60
1 answer:
Hello,
P(x)=x^3+2x²-23x-60
P(-4)=(-4)^3+2*(-4)²-23*(-4)-60=0
P(-3)=(-3)^4+2*(-3)²-23*(-3)-60=0
P(5)=5^3+2*5²-23*5-60=0
Zeros are -4,-3,5
You might be interested in
Answer:
the answer is d
Step-by-step explanation:
Answer:
point c is the intersection of line AB and ED
Answer:
5.71428571429
Step-by-step explanation:
Which question do u need help with
Answer:
10. MN=17.9 in
11. ST= 4.1 cm
12. CE= 13.0 yd
Step-by-step explanation: hope this helps :)