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madam [21]
3 years ago
12

Find the zeros of x3 +2X^2-23x-60

Mathematics
1 answer:
laila [671]3 years ago
5 0
Hello,

P(x)=x^3+2x²-23x-60
P(-4)=(-4)^3+2*(-4)²-23*(-4)-60=0
P(-3)=(-3)^4+2*(-3)²-23*(-3)-60=0
P(5)=5^3+2*5²-23*5-60=0
Zeros are -4,-3,5


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  ▶︎◆◇◆◇◆◇◆◇◆◇◆◇◆◇◆◇◆◇◆◇◆◇◆◇◆◇◆◇◆◇◀︎

Hello There!

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Procedure:

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Greetings!

--

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