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mojhsa [17]
3 years ago
5

Through music we can communicate more then what can be expressed with words alone True or false

Mathematics
2 answers:
cupoosta [38]3 years ago
6 0
 i believe it is true.<span />
alexandr1967 [171]3 years ago
4 0
I believe it is true because music has many expressions. Like for example, a violin(that’s what I play) can be played that it is singing the songs. I believe music is such a important thing in life.
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Find the dimensions of the rectangle with largest area that can be inscribed in an equilateral triangle with sides of 1 unit, if
prohojiy [21]
<span>Maximum area = sqrt(3)/8 Let's first express the width of the triangle as a function of it's height. If you draw an equilateral triangle, then a rectangle using one of the triangles edges as the base, you'll see that there's 4 regions created. They are the rectangle, a smaller equilateral triangle above the rectangle, and 2 right triangles with one leg being the height of the rectangle and the other 2 angles being 30 and 60 degrees. Let's call the short leg of that triangle b. And that makes the width of the rectangle equal to 1 minus twice b. So we have w = 1 - 2b b = h/sqrt(3) So w = 1 - 2*h/sqrt(3) The area of the rectangle is A = hw A = h(1 - 2*h/sqrt(3)) A = h*1 - h*2*h/sqrt(3) A = h - 2h^2/sqrt(3) We now have a quadratic equation where A = -2/sqrt(3), b = 1, and c=0. We can solve the problem by using a bit of calculus and calculating the first derivative, then solving for 0. But since this is a simple quadratic, we could also take advantage that a parabola is symmetrical and that the maximum value will be the midpoint between it's roots. So let's use the quadratic formula and solve it that way. The 2 roots are 0, and 1.5/sqrt(3). The midpoint is (0 + 1.5/sqrt(3))/2 = 1.5/sqrt(3) / 2 = 0.75/sqrt(3) So the desired height is 0.75/sqrt(3). Now let's calculate the width: w = 1 - 2*h/sqrt(3) w = 1 - 2* 0.75/sqrt(3) /sqrt(3) w = 1 - 2* 0.75/3 w = 1 - 1.5/3 w = 1 - 0.5 w = 0.5 The area is A = hw A = 0.75/sqrt(3) * 0.5 A = 0.375/sqrt(3) Now as I said earlier, we could use the first derivative. Let's do that as well and see what happens. A = h - 2h^2/sqrt(3) A' = 1h^0 - 4h/sqrt(3) A' = 1 - 4h/sqrt(3) Now solve for 0. A' = 1 - 4h/sqrt(3) 0 = 1 - 4h/sqrt(3) 4h/sqrt(3) = 1 4h = sqrt(3) h = sqrt(3)/4 w = 1 - 2*(sqrt(3)/4)/sqrt(3) w = 1 - 2/4 w = 1 -1/2 w = 1/2 A = wh A = 1/2 * sqrt(3)/4 A = sqrt(3)/8 And the other method got us 0.375/sqrt(3). Are they the same? Let's see. 0.375/sqrt(3) Multiply top and bottom by sqrt(3) 0.375*sqrt(3)/3 Multiply top and bottom by 8 3*sqrt(3)/24 Divide top and bottom by 3 sqrt(3)/8 Yep, they're the same. And since sqrt(3)/8 looks so much nicer than 0.375/sqrt(3), let's use that as the answer.</span>
7 0
3 years ago
Read 2 more answers
70% of days in june were sunny how many days were sunny
goblinko [34]

There are 30 days in June. So 30 days represent 100% of the days:

30 = 100%    &   x = 70%  

so 100x= 2100

x= 21  Days

I hope this helps you! =^-^=

6 0
3 years ago
if you want to compare a fraction and a decimal, why do you need to convert them to same type of number?
GaryK [48]
You need to covert the decimal to a fraction and then if they have the same denominator then compare by the numerator if they don’t the same denominator then change so they do have one then compare
6 0
3 years ago
SAT A bag contains 3 red marbles, 2 green
Alina [70]

Answer:

\frac{1}{21}

Step-by-step explanation:

refer to solution in picture

8 0
3 years ago
Lovell decorates reclaimed shorts and sells them. She pays $420 per month in rent and $21 in expenses for each pair of shorts. S
kirill [66]
Answer: 30 pairs of shorts

21x+420=35x
subtract 21x from both sides of the equation.
420=14x
get rid of the x by division
420/14
you get 30 =x
8 0
3 years ago
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