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Mariulka [41]
3 years ago
12

If there are 12 people sitting at a round table , how many different pairs of people can have conversations during dinner, assum

ing the can all talk to each other? What geometric figure can you use t model this situation?
Mathematics
2 answers:
julsineya [31]3 years ago
7 0
66 different pairs. Use a dodecagon showing sides and angles
kherson [118]3 years ago
5 0

Answer:

Step-by-step explanation:

Given that there are 12 people sitting around at a table.

We see that any two persons can have conversations.  If we count A with B as one conversation this is the same as B with A

i.e. order does not matter

So here we have to use combinations.

2 people out of 12 where order does not matter can be done in 12C2 ways

No of conversations = 12C2\\= \frac{12!}{2!10!} \\=66

If we use a dodedecon as a geometrical figure with 12 vertices representing 12 persons the conversation between pairs can be associated with all diagonals and sides connecting two vertices.

Sides are 12 and diagonals are 54 totalling 66.

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There are 4 quarters, 5 nickels and 3 dimes in a jar. One coin is randomly drawn,
vagabundo [1.1K]

Answer:

\displaystyle\frac{5}{36}

Step-by-step explanation:

Probability is used to find how likely an outcome is to happen. Probability can be expressed as a fraction with the total outcomes as the denominator and the number of successful outcomes (what you want to happen) as the numerator.

Sample Size

The sample size is the number of possible outcomes. In this case, the sample size will be the total number of coins. To find the sample size we need to add together all of the coins.

  • 4 + 5 + 3 = 12

This means that the sample size is 12. For this type of probability, the sample size will serve as the denominator for each probability.

Replacement

In the question, it is stated that coins are replaced. This means that the sample size will not change at any point. So, the denominator will be the same for every probability.

Creating Probability Fractions

We are looking for the probability of getting a quarter and nickel, so we need to find the fractions that represent both situations.

First, let's find the quarter. As stated in the first paragraph, the number of successful outcomes is the numerator. There are 4 quarters, so 4 is the number of successful outcomes. Therefore, 4 will be the numerator. Then, 12 will be the denominator because 12 is the sample size.

  • \displaystyle\frac{4}{12}

Next, we need to find the probability of a nickel. Since there are 5 nickels, there are 5 successful outcomes. Then, the sample size is still 12 because there is replacement.

  • \displaystyle\frac{5}{12}

Complex Probability

Now we have the probability of both a quarter and nickel alone. However, this question asks about the probability of both, so this is an example of complex probability. To find complex probability, you have to multiply each probability together.

  • \displaystyle\frac{4}{12} *\frac{5}{12}=\frac{20}{144}

To reach the final answer we have to simplify the answer.

  • \displaystyle\frac{20}{144} =\frac{5}{36}

This means that the probability of pulling a quarter and then a nickel is 5/36.

3 0
2 years ago
Compute the permutation. A chemist has eight test tubes to examine. In how many orders can he do this examination? 16,777,216 20
Talja [164]

Answer:

40,320

Step-by-step explanation:

He can pick any one of the eight for the first examination.

He can pick any one of the remaining 7 for the 2nd examination.

He can pick any one of the remaining 6 for the 3rd examination.

...

He can pick any one of the remaining 2 for the 7th examination.

There's one left for the 8th examination.

Thus, there are 8×7×6×5×4×3×2×1 = 8! = 40,320 different possible orders in which the tubes can be examined.

6 0
3 years ago
Help me pleaseeeeeeeeeeeeeee
sineoko [7]
<h3>Answer:   </h3><h3>A) 729</h3><h2>Step-by-step explanation:</h2>

The number of trees are multiplied by 3 each week.

<h3>                  Weeks)   1     2     3     4       5         6          <em><u>7</u></em></h3><h3>Number of Trees)   1     3     9     27     81     243      <u><em>729</em></u> </h3><h3></h3><h3></h3><h3>I hope that helped</h3><h3>]</h3><h3></h3><h3>Sincerely, 4018669</h3>
5 0
3 years ago
A bag contains yellow marbles and red marbles, 77 in total. The number of yellow marbles is 5 more than 3 times the number of re
bulgar [2K]

Answer:

41

Step-by-step explanation:

yellow marbles=5+ 3r(r is the number of red marbles)

red marbles=3r

3r+3r+5=77

6r=77-5

6r=72

r=72/6=12

yellow marbles = 5 + 3r

5+ 12 x 3

5+ 36

=41

8 0
2 years ago
Find the solution of this system of equations. Separate the x- and y- values with a comma. x-2y=-24 and x-y=4
defon
X - 2y = -24
x - y = 4

Isolate x in the first equation by adding 2y to both sides.
x = -24 + 2y  

Now plug in this value of x into the second equation.
(-24 + 2y) - y = 4
Solve. Combine all like terms, 2y - y.
-24 + y = 4
Add 24 to both sides to isolate y.
y = 28

Now plug y back into the first equation to find x.
x - 2(28) = -24
x - 56 = -24
Add 56 to both sides to isolate x.
x = 32

The solution is (32, 28).
6 0
3 years ago
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