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RoseWind [281]
2 years ago
9

Identify the variable expression that is not a polynomial. A. 23 B. + 2 C. y + 1 D. x12

Mathematics
1 answer:
myrzilka [38]2 years ago
4 0
A polynomial consists of several terms so A.23
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Solve: g^2x+1=g^3x-2<br> x=?
Schach [20]

Answer:

the answer you will be looking for is g^2x - g^3x = -3

Step-by-step explanation:

as much as I would like to, I'm really not that great at explaining things

6 0
2 years ago
Someone who's good at math please help me!!!
timurjin [86]
#1.
Here what you do is cross multiply.
\frac{8x}{13x}
#2.
Same as #1, just cross multiply.
\frac{9x}{12}

You get the gist?
8 0
3 years ago
Subtract the following polynomials, then place the answer in the proper location on the grid.
melamori03 [73]
When we add or subtract polynomials, the addition or subtraction is applied to the coefficients of the terms of equal powers.

For the given polynomials, we are required to do subtraction as follows:
(-4.1 x^2 + 0.9 x - 9.8) - (1.7 x^2 - 2.4 x - 1.6)
= -4.1 x^2 + 0.9 x - 9.8 - 1.7 x^2 + 2.4 x + 1.6
= (-4.1-1.7) x^2 + (0.9+2.4) x + (-9.8+1.6)
= -5.8 x^2 + 3.3 x - 8.2

The final expression (solution) is:
-5.8 x^2 + 3.3 x - 8.2

8 0
3 years ago
Five times the sum of a number and 3 is equal to twenty
drek231 [11]

5x3 is ur answer!!!! :)

7 0
3 years ago
Read 2 more answers
Manuel bought a balloon (that is a perfect sphere) with a radius of 2 \text{ cm}2 cm2, space, c, m. He wanted his balloon to be
jonny [76]
The original volume of the balloon is given by:
 V1 = (4/3) * (pi) * (r ^ 3)
 Where,
 r: radius of the sphere.
 Substituting values:
 V1 = (4/3) * (pi) * (1 ^ 3)
 V1 = (4/3) * (pi) * (1)
 Then, the volume of the current sphere is:
 V2 = (4/3) * (pi) * ((1 + 2 * (1)) ^ 3)
 V2 = (4/3) * (pi) * ((1 + 2) ^ 3)
 V2 = (4/3) * (pi) * ((3) ^ 3)
 V2 = (4/3) * (pi) * (27)
 The relation of volumes is:
 V2 / V1 = ((4/3) * (pi) * (27)) / ((4/3) * (pi) * (1))
 V2 / V1 = 27/1
 Answer:
 
The ratio of the current volume of the balloon to the original volume of the balloon is:
 
27: 1
6 0
3 years ago
Read 2 more answers
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