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Firlakuza [10]
3 years ago
6

Smallest to biggest 0.43,3/7,43.8%,7/16

Mathematics
1 answer:
Snezhnost [94]3 years ago
8 0
First, we need to convert all the givens to decimal numbers. This will ease the arrangement process.
0.43 is already given as a decimal
3/7 is equal to 0.428
43.8% is equal to 0.438
7/16 is equal to 0.4375

Now, it has become easy to arrange the givens from smallest to biggest as follows:
0.428 , 0.43 , 0.4375 , 0.438

Changing the decimals back to the given form, we will find that the arrangement from the smallest to the biggest is as follows:
3/7 , 0.43 , 7/16 , 43.8% 

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Steve can text 20 emojis in 24 seconds.At that rate,how many emojis can he text in 2 minutes and 48 seconds
Lelu [443]

Answer:140

Step-by-step explanation:

24/20=168/N

Cross product

24×n=168×20

24n=3360

n=3360/24

n=140

8 0
3 years ago
Which inequality is represented by this graph? <br>​
erica [24]

Answer:

x > 4

Step-by-step explanation:

Because x is greater than 4

6 0
3 years ago
How do I factor out a constant before factoring out a quadratic? <br>Factor completely: 3w^2-3w-90
pantera1 [17]
3w^2-3w-90 =0 \ \ \:3 \\ \\w^2- w-30 =0 \\ \\a=1 , \ b= -1 , c= -30 \\ \\\Delta =b^2-4ac = (-1)^2 -4\cdot1\cdot (-30) =1+120=121 \\ \\w_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{1-\sqrt{121}}{2 }=\frac{ 1-11}{2}=\frac{-10}{2}=-5

w_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{1+\sqrt{121}}{2 }=\frac{ 1+11}{2}=\frac{12}{2}=6 \\ \\ Answer:\\ \\ w^2- w-30 =(x+5)(x-6)
 

3 0
3 years ago
How many different linear arrangements are there of the letters a, b,c, d, e for which: (a a is last in line? (b a is before d?
inna [77]
A) Since a is last in line, we can disregard a, and concentrate on the remaining letters.
Let's start by drawing out a representation:

_ _ _ _ a

Since the other letters don't matter, then the number of ways simply becomes 4! = 24 ways

b) Since a is before d, we need to account for all of the possible cases.

Case 1: a d _ _ _ 
Case 2: a _ d _ _
Case 3: a _ _ d _
Case 4: a _ _ _ d

Let's start with case 1.
Since there are four different arrangements they can make, we also need to account for the remaining 4 letters.
\text{Case 1: } 4 \cdot 4!

Now, for case 2:
Let's group the three terms together. They can appear in: 3 spaces.
\text{Case 2: } 3 \cdot 4!

Case 3:
Exactly, the same process. Account for how many times this can happen, and multiply by 4!, since there are no specifics for the remaining letters.
\text{Case 3: } 2 \cdot 4!

\text{Case 4: } 1 \cdot 4!

\text{Total arrangements}: 4 \cdot 4! + 3 \cdot 4! + 2 \cdot 4! + 1 \cdot 4! = 240

c) Let's start by dealing with the restrictions.
By visually representing it, then we can see some obvious patterns.

a b c _ _

We know that this isn't the only arrangement that they can make.
From the previous question, we know that they can also sit in these positions:

_ a b c _
_ _ a b c

So, we have three possible arrangements. Now, we can say:
a c b _ _ or c a b _ _
and they are together.

In fact, they can swap in 3! ways. Thus, we need to account for these extra 3! and 2! (since the d and e can swap as well).

\text{Total arrangements: } 3 \cdot 3! \cdot 2! = 36
7 0
3 years ago
The quotient of two numbers is 3 and their sum is 8 what are he two numbers
Nezavi [6.7K]
<h2>Translating Word Equations into Numerical Equations</h2>

To change words into equations, we can recognize keywords that translate into operations and/or numbers:

  • <em>quotient</em> = divide
  • <em>a number/the number/two numbers</em> = variables
  • <em>sum</em> = add

<h2>Solving the Question</h2>

Let the two numbers be <em>a</em> and <em>b</em>.

We're given:

  • quotient of <em>a</em> and <em>b</em> is 3
    ⇒ \dfrac{a}{b}=3
  • sum of <em>a</em> and <em>b</em> is 8
    ⇒ a+b=8

First, isolate <em>a</em> in the first equation and substitute it in the second equation to solve for <em>b</em>:

\dfrac{a}{b}=3\\\\a=3b

a+b=8\\3b+b=8\\4b=8\\b=2

Therefore, one of the numbers is 2. Substitute this into one of our equations to solve for <em>a</em>:

a+b=8\\a+2=8\\a=6

Therefore, the other number is 6.

<h2>Answer</h2>

The two numbers are 2 and 6.

4 0
2 years ago
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