Answer:
At the same rate 18 carburetors out of 1,050 could be expected to be detective.
Step-by-step explanation:
The number of carburetors tested = 175
Defective pieces out o f 175 = 3
So, ratio of defected to tested = 3 : 175
Now, the number of carburetors tested in second batch = 1,050
Here, let the defective pieces = m
So, by the Ratio of Proportion,
![\frac{3}{175} = \frac{m}{1050}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B175%7D%20%20%3D%20%5Cfrac%7Bm%7D%7B1050%7D)
or, ![m = \frac{1050 \times 3}{175} = 18](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B1050%20%20%5Ctimes%203%7D%7B175%7D%20%20%3D%2018)
⇒ m = 18
Hence, at the same rate 18 carburetors out of 1,050 could be expected to be detective.