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BlackZzzverrR [31]
3 years ago
8

Enter the ordered pair for point J.

Mathematics
2 answers:
AfilCa [17]3 years ago
8 0
I think it is (1,1.5)
Furkat [3]3 years ago
8 0

Answer:

-2.5, 1.5

good luck

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Hi there! i going to fail if you don´t answer :D :D
NARA [144]

Answer:

it will be 1/2

Step-by-step explanation:

because x×y={(6,2), (6, 8),(9,2), (9, 8)}

5 0
4 years ago
Hailey is making 36 mini- pumpkin pies. Each pie takes 6 ounces of pumpkin. The cans of pumpkin are 2 pounds each. How many can
serious [3.7K]
1 pound = 16 ounces

6 ounces each pie

36 mini pies to make

36 × 6 = 216 ounces needed to make 36 mini pies

216 ÷ 16 = 13.5 pounds
if each can of pumpkin is 2 pounds,
13.5 ÷ 2 = 6.75 so that would be 7 cans of pumpkin
3 0
3 years ago
Find f(−2) given that f(x)=2x2−3x+7.
Sedaia [141]

Answer:

21.

Step-by-step explanation:

f(x) = 2x^2 - 3x + 7.

When x = -2,

f(-2) = 2(-2)^2 - 3(-2) + 7

= 2(4) - (-6) + 7

= 8 + 6 + 7

= 21.

3 0
3 years ago
Read 2 more answers
A 10-pound block of ice melts at a rate of 3% per hour. Find the weight of the block of ice after 1 day.
mylen [45]

Answer:

The weight of the block of ice after 1 day is of 4.81 pounds.

Step-by-step explanation:

Equation for exponential decay:

The equation that models an amount after t hours, subject to exponential decay, is given by:

A(t) = A(0)(1 - r)^t

In which A(0) is the initial amount and r is the decay rate, as a decimal.

A 10-pound block of ice melts at a rate of 3% per hour.

This means that A(0) = 10, r = 0.03

So

A(t) = A(0)(1 - r)^t

A(t) = 10(1 - 0.03)^t

A(t) = 10(0.97)^t

Find the weight of the block of ice after 1 day.

One day has 24 hours, so this is A(24).

A(24) = 10(0.97)^{24} = 4.81

The weight of the block of ice after 1 day is of 4.81 pounds.

6 0
3 years ago
If someone solved this can you help?
natka813 [3]

Answer:

I/d/k but I will say 9/10

Step-by-step explanation:

Wow

5 0
3 years ago
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