Answer:
Daughter cells with abnormal number of chromosomes will be produced (aneuploidy)
Explanation:
Ideally, homologous pair of chromosomes are meant to separate into opposite poles during the anaphase I stage of meiosis. However, a failure to separate, a process called MEIOTIC NON-DISJUNCTION, will cause some daughter cells to have more than the required/normal chromosome number while some daughter cells will have less than the normal or no chromosome.
This abnormality in chromosome number caused by failure of chromosome to separate is called ANEUPLOIDY. In a nutshell, when this occurs, the daughter cells will possess abnormalities in chromosome number i.e trisomy, monosomy etc.
an organelle that releases energy for metabolic activity in a nerve cell is the what
the mitochondria
Answer:
The correct answer is - Methionine, serine, histidine, aspartate, glycine
Explanation:
The new segment of DNA is: 3'-TACAGGGTGCTACCCACT-5', which performs two processes to form a peptide chain, transcription, and translation. In transcription, the DNA segment is encoded to an mRNA molecule which has its complementary sequence to DNA sequence.
New DNA strand: 3'-TACAGGGTGCTACCCACT-5'
mRNA sequence: 3'-AUGUCCCACGAUGGGUGA-5'
The translation of this mRNA would be on the basis of chart
AUG - Methionine (start codon)
UCC - serine
CAC - histidine
GAU - aspartate
GGG - glycine
UGA - stop codon
The peptide chain would be - Methionine, serine, histidine, aspartate, glycine
According to Mendel Law of segregation all offspring in F1 generation will white wool. However, in F2 generation three will be white wool and only one offspring will be spotted wool.
Phenotype (parental generation) White wool x spotted wool
Genotype TT tt
F1 generation Tt, Tt,Tt, Tt (white wool)
Self cross Tt x Tt
F2 generation TT, Tt, Tt, tt
white wool = 3
spotted wool = 1
