Using Sine.

Sine = Opposite / Hypotenuse

sin 60° = a / (6√3) But sin60° = √3/2

√3/2 = a/(6√3)

Cross multiply

2*a = 6√3 * √3

2a = 6 * √(3*3)

2a = 6*3

a = 6*3/2

a = 3*3 = 9

Option E.

Hope this helps.

4 0

3 years ago

A gym has 2kg and 5kg weights. There are 10 disks in all. The total weight of 2kg and 5kg disks is equal to 29kg. Find the numbe

Simora [160]

Answer:

no of 5 kg disks is 3, and no of 2 kg disks is (10-3) i.e. 7

Step-by-step explanation:

Let the no of 2kg disks be a.

Let no of 5 kg disks be b.

2a+5b=29

a+b=10

Using substitution, we have

2(10-b) + 5b=29

20-2b+5b=29

20+3b=29

3b=9

b=3

So no of 5 kg disks is 3, and no of 2 kg disks is (10-3) i.e. 7

6 0

3 years ago

Mateo reproducira una foto que mide 5 cm por lado a una escala de 3/4

Aneli [31]

the question in English

Mateo will reproduce a photo measuring 5 cm per side on a scale of 3/4

How much will the square side of the copy measure?

Will the size of the copy be larger or smaller than the original?

we know that

the scale factor is equal to $\frac{3}{4}$

Let

x----------> the original length side

y--------> the copy length side

$y=\frac{3}{4}*x$

we have that

$x=5\ cm$

substitute the values

$y=\frac{3}{4}*5=3.75\ cm$

therefore

<u>the answer Part a) is </u>

the length side of the copy measure is $3.75\ cm$

Part b)

we know that

the size of the original photo is------> $5*5=25\ cm^{2}$

the size of the copy is------> $3.75*3.75=14.06\ cm^{2}$

$14.06\ cm^{2} < 25\ cm^{2}$

therefore

<u>the answer part b) is</u>

The size of the copy be smaller than the original

3 0

3 years ago

A teacher is giving her students a lesson on inequalities and asks the class to suggest points that are included in the solution

Slav-nsk [51]

Neither of the students are correct

8 0

3 years ago