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Hitman42 [59]
3 years ago
6

A city has a populations of 38,802,500 people. estimate the population ot hte nearest ten million

Mathematics
1 answer:
Zolol [24]3 years ago
8 0

Answer:

39,000,000

Roundend to the nearest 1,000,000 or

the Millions Place.

38,802,500.0000000

Roundend to the nearest 0.0000001 or

the Ten Millionths Place.

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Find the value of x in the triangle shown below
JulijaS [17]

Answer:

x = 3

Step-by-step explanation:

we can use the Pythagorean theorem to solve this problem

x^2 + 4^2 = 5^2

x^2 + 16 = 25

x^2 = 9

x = +/- 3

we take only the positive value because a length can‘t be negative

x = 3

5 0
3 years ago
PLEASE!!!
ANEK [815]

9514 1404 393

Answer:

  1. 30m +50 = 20m +100
  2. m = 5
  3. yes. symmetric property of equality.

Step-by-step explanation:

1. The expression for c in the first equation is (30m+50). Substituting that for c in the equation ...

  c = 20m +100

gives you ...

  30m +50 = 20m +100

__

2. Adding -50-20m to both sides gives ...

  10m = 50

  m = 5 . . . . . . . divide by 10

__

3. Doing the substitution in reverse, you would substitute (20m+100) for c in the equation ...

  c = 30m +50

to get ...

  20m +100 = 30m +50

This is the equation of part 1 with the expressions swapped to the other side of the equal sign. The symmetric property of equality tells you that changing sides of the equal sign does not change the value of the variable(s).

You get the same solution.

3 0
3 years ago
-5/6x-7/30x+1/5x-52 please help me guys cuz imk not good with math
Marina CMI [18]

Answer:

\frac{-13}{15} x-52

Step-by-step explanation:

\frac{-5}{6}x-\frac{7}{30}x+\frac{1}{5}x-52

=\frac{-5}{6}x+\frac{-7}{30}x+\frac{1}{5}x+-52

Combine Like Terms:

=\frac{-5}{6}x+\frac{-7}{30}x+\frac{1}{5}x+-52

=(\frac{-5}{6}x+\frac{-7}{30}x+\frac{1}{5}x)+(-52)

=\frac{-13}{15}x+-52

Therefore, \frac{-13}{15}x+-52 will be your final answer.

7 0
2 years ago
Which is the largest interval over which the function shown in the table is decreasing
jeka57 [31]
Okay the answer is b
8 0
3 years ago
two cars travel at same speed to different destinations. car A reaches its destination in 24 minutes. car B reaches its destinat
Harlamova29_29 [7]

Answer:

The speeds of the cars is: 0.625 miles/minute

Step-by-step explanation:

We use systems of equations in two variables to solve this problem.

Recall that the definition of speed (v) is the quotient of the distance traveled divided the time it took : v=\frac{distance}{time}. Notice as well that the speed of both cars is the same, but their times are different because they covered different distances. So if we find the distances they covered, we can easily find what their speed was.

Writing the velocity equation for car A (which reached its destination in 24 minutes) is:

v\,*\,24\,min=d_A

Now we write a similar equation for car B which travels 5 miles further than car A and does it in 32 minutes:

v\,*\,32\,min=d_A+5\,miles

Now we solve for d_A in this last equation and make the substitution in the equation for car A:

v\,*\,32\,min=d_A+5\,miles\\d_A=v\,*\,32\,min-5\,miles\\\\v\,*\,24\,min=v\,*\,32\,min-5\,miles\\v\,(24\,min-32\,min)=-5\,miles\\v\,(-8\,min)=-5\, miles\\v=\frac{-5}{-8} \frac{miles}{min} \\v=0.625\,\frac{miles}{min}

So this is the speed of both cars: 0.625 miles/minute

3 0
3 years ago
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