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Archy [21]
4 years ago
12

Find the area of the composite figure.

Mathematics
1 answer:
iogann1982 [59]4 years ago
6 0

Answer:

1048.32 or 432 pi

Step-by-step explanation:

12*12=144

144+(4/3 pi *6^3)

6*6*6=216

216*4/3pi=864/3

864/3=288

288*3.14(pi)=904.32

904.32+144=1048.32

(If you have the pi symbol the answer is 144+288=432pi)

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Terry sees an offer about a refurbished phone which is 35% off the original price the new price is £78 how much was the phone be
erica [24]

part/whole=0.65

78/whole=0.65

whole =78/0.65 =120 £

5 0
3 years ago
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Ax-b=c solve for b<br> A- b= -ax-c<br> B- b=ax+c<br> C- b= -ax+c<br> D- b=ax-c
Alex
Ax - b = c....subtract ax from both sides
-b = -ax + c <==
or it could also have been b = ax - c (but that ones not there)
6 0
3 years ago
8+ 6+ 4+ 2+ 2 ++ 6 8 -8 -6 -4 2 ܠܛ -4+ -6+ -8+ What is the equation of the line?
VMariaS [17]

The lines whose equation is x = a, are vertical lines that pass through the point (a, y) where y is any real number. Additionally, vertical lines have an indefinite slope.

You can see it in the graph of this equation:

5 0
2 years ago
Rectangle divided into four rectangles. The perimeters of rectangle #1, #2, #3, #4 are 10 cm, 20 cm, 28 cm and 18 cm respectivel
notsponge [240]

Answer:

Perimeter of big rectangle = 38 units

Step-by-step explanation:

Let the sides of rectangle (1) = a and c cm

Sides of rectangle (2) = b and c cm

Sides of rectangle (3) = b and d cm

Sides of rectangle (4) = a and d cm

Perimeter of (1) = 2(length + width)

2(a + c) = 10

a + c = 5 ---------(1)

Perimeter of (2) = 2(b + c)

2(b + c) = 20

b + c = 10 -------(2)

Perimeter of (3) =2(b + d)

2(b + d) = 28

b + d = 14 --------(3)

Perimeter of (4) = 2(a + d)

2(a + d) = 18                      

a + d = 9 -------(4)

Since perimeter of the big rectangle = 2(a + b + c + d)

By adding equations (1) + (2) + (3) + (4),

(a + c) + (b + c) + (b + d) + (a + d) = 5 + 10 + 14 + 9

2(a + b + c + d) = 38

Therefore, perimeter of the rectangle ABCD = 38 units

7 0
3 years ago
Can u guys PLEASE answer this question ASAP.
Anastasy [175]

Answer:

93.75 Kg

Step-by-step explanation:

Farmer spreads 25 kg fertilizer over an area of 4000 m square .

So, Over 1 m square , \frac{25}{4000} kg of fertilizer will be needed

As we know , 1 hectare = 10,000 m square.

So, 1.5 hectare equals 15,000 m square.

So, for 15,000 m square , Fertilizer needed will be equal to                                      \frac{25}{4000} ×15,000 = 93.75 Kg

So, 93.75 Kg of fertilizer is needed for 1.5 ha of land.

                                     

4 0
3 years ago
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