Find a polynomial function of degree 3 such that f (2) = 24 and x– 1, x and x+ 2
1 answer:
f(x) = 3x³ + 3x² - 6x
given the factors of the polynomial , then
f(x) =ax(x - 1)(x + 2) ( a is a multiplier )
to find a use f(2) = 24
f(2) = 2a(1)(4) = 24 ⇒8a = 24 ⇒ a = 3, thus
f(x) = 3x(x² + x - 2) = 3x³ + 3x² - 6x
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Domain: (-∞,∞)
Range: (-∞,1]
Answer:
x = 9
Step-by-step explanation:
5x+4 = 49
subtract 4 from both sides
5x = 45
divide both sides by 5
x = 9
Well you can see it would be mixed number and it is not a number less than 1
ABOUT POINT SLOPE FORM:
- y - Y1 = m(x - X1)
- m represents the slope
- Y1 & X1 is a point
- The form allows you to identify the slope & the point on the line
y - Y1 = m(x - X1)
y - 8 = -1/10(x - 1) -- IN POINT SLOPE FORM
Hope this helps you!!! :)
Answer:
It's true. We can write integers in fraction by giving it a denominator of 1.
