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Tamiku [17]
3 years ago
9

You can undo up to the most recent 40 actions by clicking the undo button.

Computers and Technology
1 answer:
Cloud [144]3 years ago
6 0
The answer is true. The Undo command is set up on the toolbar.  You can undo up to 40 edits in your plan by clicking on the Undo button.  If you want to undo all of the revises made, simply quit (close your Internet browser window or start a new plan) without saving. 
You might be interested in
outline 4 IDE features that makes software development much faster and more convenient than other alternatives.​
mr_godi [17]

Answer:

IDEs can let you code without internet.

Explanation:

1. you can code without wifi.

2. it combines common developer tools into 1 GUI (grafic user interface).

3. it gives a warning about memory leaks.

4. it can correct synaxes.

Hope This Helps! :)

3 0
3 years ago
52.
OLEGan [10]
For the first one its NOW, I'm not sure about the 2nd, the 3rd I think is penal code cases but i could be wrong, and the 4th one sounds like voting is the most logical answer. 
7 0
3 years ago
If Anime Characters were real , Who Would Your Anime Wife Would Be (Tell Who And Why)
ehidna [41]

Answer:

Runa, because  she’s like me I r l lol

Explanation:

3 0
3 years ago
Write a program that gets a list of integers from input, and outputs the integers in ascending order (lowest to highest). The fi
Travka [436]

Answer:

Explanation:

Since no programming language is stated, I'll use Microsoft Visual C# in answering this question.

// C# program sort an array in ascending order

using System;

class SortingArray {

int n; //number of array elements

int [] numbers; //Array declaration

public static void Main() {

n = Convert.ToInt32(Console.ReadLine());

numbers = new int[n];

for(int i = 0; i<n; I++)

{

numbers [n] = Convert.ToInt32(Console.ReadLine());

}

SortArray();

foreach(int value in numbers)

{

Console.Write(value + " ");

}

}

void SortArray()

{

int temp;

// traverse 0 to array length

for (int i = 0; i < numbers.Length - 1; i++)

// traverse i+1 to array length

for (int j = i + 1; j < numbers.Length; j++){

// compare array element with all next element

if (numbers[i] < numbers[j])

{

temp = numbers[i];

numbers[i] = numbers[j];

numbers[j] = temp;

}

}

}

5 0
3 years ago
Complete function PrintPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 3, print "To
SVETLANKA909090 [29]

Answer:

<h2>Function 1:</h2>

#include <stdio.h> //for using input output functions

// start of the function PrintPopcornTime body having integer variable //bagOunces as parameter

void PrintPopcornTime(int bagOunces){

if (bagOunces < 3){ //if value of bagOunces is less than 3

 printf("Too small"); //displays Too small message in output

 printf("\n"); } //prints a new line

//the following else if part will execute when the above IF condition evaluates to //false and the value of bagOunces is greater than 10

else if (bagOunces > 10){

    printf("Too large"); //displays the message:  Too large in output

    printf("\n"); //prints a new line }

/*the following else  part will execute when the above If and else if conditions evaluate to false and the value of bagOunces is neither less than 3 nor greater than 10 */

else {

/* The following three commented statements can be used to store the value of bagOunces * 6 into result variable and then print statement to print the value of result. The other option is to use one print statement printf("%d",bagOunces * 6) instead */

    //int result;

    //result = bagOunces * 6;

    //printf("%d",result);

 printf("%d",bagOunces * 6);  /multiplies value of bagOunces  to 6

 printf(" seconds");

// seconds is followed with the value of bagOunces * 6

 printf("\n"); }} //prints a new line

int main(){ //start of main() function body

int userOunces; //declares integer variable userOunces

scanf("%d", &userOunces); //reads input value of userOunces

PrintPopcornTime(userOunces);

//calls PrintPopcornTime function passing the value in userOunces

return 0; }

Explanation:

<h2>Function 2:  </h2>

#include <stdio.h> //header file to use input output functions

// start of the function PrintShampooInstructions body having integer variable numCycles as parameter

void PrintShampooInstructions(int numCycles){

if(numCycles < 1){

//if conditions checks value of numCycles is less than 1 or not

printf("Too few."); //prints Too few in output if the above condition is true

printf("\n"); } //prints a new line

//else if part is executed when the if condition is false and else if  checks //value of numCycles is greater than 4 or not

else if(numCycles > 4){

//prints Too many in output if the above condition is true

printf("Too many.");

printf("\n"); } //prints a new line

//else part is executed when the if and else if conditions are false

else{

//prints "N: Lather and rinse." numCycles times, where N is the cycle //number, followed by Done

for(int N = 1; N <= numCycles; N++){

printf("%d",N);

printf(": Lather and rinse. \n");}

printf("Done.");

printf("\n");} }

int main() //start of the main() function body

{    int userCycles; //declares integer variable userCycles

   scanf("%d", &userCycles); //reads the input value into userCycles

   PrintShampooInstructions(userCycles);

//calls PrintShampooInstructions function passing the value in userCycles

   return 0;}

I will explain the for loop used in PrintShampooInstructions() function. The loop has a variableN  which is initialized to 1. The loop checks if the value of N is less than or equal to the value of numCycles. Lets say the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 1<2. So the program control enters the body of loop. The loop body has following statements. printf("%d",N); prints the value of N followed by

printf(": Lather and rinse. \n"); which is followed by printf("Done.");

So at first iteration:

printf("%d",N); prints 1 as the value of N is 1

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

1: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 2.

Now at second iteration:

The loop checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 2=2. So the program control enters the body of loop.

printf("Done."); prints Done after the above two lines.

printf("%d",N); prints 2 as the value of N is 2

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

2: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 3.

The loop again checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to false as N<numCycles  which means 3>2. So the loop breaks.

Now the next statement is:

printf("Done."); which prints Done on the screen.

So as a whole the following output is displayed on the screen:

1: Lather and rinse.

2: Lather and rinse.

Done.

The programs along with their outputs are attached.

6 0
3 years ago
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